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faltersainse [42]
3 years ago
11

They did a flu shot from McKinnon at 45° to the horizontal with an initial speed of 25 m/s and that is positioned at a horizonta

l distance of 50 m from the canyon from which it is shot how long does it take the daredevil to travel the 50 m horizontally
Physics
1 answer:
Margarita [4]3 years ago
6 0

Answer:

The time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

Explanation:

Given;

angle of projection, θ = 45°

initial speed of the projectile, u = 25 m/s

horizontal distance traveled by the projectile, x = 50 m

The time taken for the daredevil to travel the 50 m horizontally is calculated as;

t =\frac{X}{u_x}

where;

u_x is the horizontal component of the velocity = uCosθ

t =\frac{X}{u Cos \ \theta} \\\\t =\frac{50}{25 \times Cos(45)} \\\\t= \frac{50}{17.678} \\\\t = 2.83 \ s

Therefore, the time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

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Once an object enters orbit, what keeps the object moving sideways?
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Answer: Inertia!!

Explanation: I just completed the edg quiz and got that answer correct! Hope its not too late for you!

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3 years ago
Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each trav
umka2103 [35]

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

v_i = 4.0 \ m/s

then,

v_f=\frac{4.0}{2}

    =2.0 \ m/s

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ a=\frac{v_f^2-v_i^2}{2s}

On substituting the given values, we get

⇒    =\frac{(2.0)^2-(4.0)^2}{2\times 18.2}

⇒    =\frac{4-8}{37}

⇒    =\frac{-4}{37}

⇒    =0.108 \ m/s^2

As we know,

⇒  f=ma

and,

⇒  \mu_rmg=ma

⇒       \mu_r=\frac{a}{g}

On substituting the values, we get

⇒       =\frac{0.108}{9.8}

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7 0
3 years ago
HEY CAN ANYONE ANSWER DIS RQ PLS!!!!
eduard

Answer:

scale and balance

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2 years ago
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A 4.4 kg marble (really big heavy marble) is accelerating down an incline. When it reaches level ground it slows down to a stop
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#A

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

\\ \rm\longmapsto Force=ma

\\ \rm\longmapsto Force=4.4(-1.74)

\\ \rm\longmapsto Force=-7.656N

#B

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

\\ \rm\longmapsto a=\dfrac{v-u}{t}

\\ \rm\longmapsto u=v-at

\\ \rm\longmapsto u=0-(-1.74)(1.27)

\\ \rm\longmapsto u=1.74(1.27)

\\ \rm\longmapsto u=2.2m/s

4 0
2 years ago
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