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AysviL [449]
3 years ago
10

The scientific study of the behavior of matter near 0 K is called

Chemistry
2 answers:
pshichka [43]3 years ago
8 0
I think it is called condensated matter
malfutka [58]3 years ago
7 0

The correct answer is cryogenics :)

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What is the name of this molecule?
sveta [45]

Answer:

The formula of the molecule given above can also be written as C4H10. 

If you count all the carbon atoms you will discover, they are four while that of hydrogen is 10.Thus, the name of the compound is ISOBUTANE [I -BUTANE]; it is also called 2 - methyl propane. Isobutane is used majorly as petrol additive in refineries; it is used in the production of isooctane, which is a octane gasoline component that enhances the octane rating and anti-knock properties of gasoline.  

Explanation:

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3 years ago
Which of the following does NOT show the law of conservation of mass?
algol [13]
I think the correct answer from the choices listed above is option B.  <span>24 mL of Mg burn in 32 mL O2 to produce 56 mL of MgO </span>does not show the law of conservation of mass. Volumes cannot be added because there are volume effects when you add different substances. So, the reactants is not equal to the product.
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3 years ago
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Balance this equation. If a coefficient of "1" is required, choose "blank" for that box.
Andrej [43]
When balancing  the  equation  you  need  to  know  how  many     moles  reacted  and  how  many were formed.To  balance  this  equation  we  require  1 moles  of  C2H4,  3moles  of  O2  to  form 2  moles CO2  and 2 moles  H2o
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4 0
3 years ago
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Magnesium bromide is prepared in a laboratory using the reaction below. Typically, the magnesium bromide is recoveted as a solid
Amiraneli [1.4K]
Can you give more examples?
6 0
3 years ago
A solution is made by mixing 0.82 grams of sodium acetate, 1 mL of 12 M acetic acid (pKa=4.76) and water to give a final volume
kompoz [17]

Answer:

This solution acts as an efficient buffer

Explanation:

the pH of a buffer solution can be described like this: pH=pKa+log\frac{[base]}{[acid]}

[acid]=[acetic acid]=1mL.\frac{12mol}{1000mL} . \frac{1}{1L} = 0.012M

[base]=[sodium acetate]=0.82g.\frac{1mol}{82g} .\frac{1}{1l} = 0.01M

replacing, pH=4.76+log\frac{0.01M}{0.012M} =4.84

If we add an acid, pH will decrease a little bit and if we add a base, pH wil increase a little bit.

lets supose that we change the rate by increasing [base] to 0.1, then

pH=4,76+log\frac{0.1}{0.012} = 5.68

and now lets supose that we increase [acid] to 0.1 pH=4.76+log\frac{0.01}{0.1} = 3.76

Big changes in concentration of base or acid doesn´t produce big changes in pH, in that way the mix of sodium acetate with acetic acid is a good buffer solution.

4 0
3 years ago
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