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pav-90 [236]
3 years ago
12

An 80 kg volleyball player lands from a jump and tries to stop her forward motion. The normal contact force exerted by the floor

on her shoes is 2000 N. The friction force exerted by the floor on her shoes is 600 N acting backward on the player. What is the resultant ground reaction force exerted by the floor on the volleyball player's shoes?
Chemistry
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

The answer to the question is

The resultant ground reaction force exerted by the floor on the volleyball player's shoes = 2088.06 N

Explanation:

To solve the queston we list out the variables thus

Mass of volley ball player = 80 kg

Normal force exerted on her shoes by the floor N =2000 N

friction force, f, exerted on her shoes backwards = 600 N

The resultant ground reactive force, R, is given by

R² = N² + f² = 2000² + 600² =  4000000 + 360000 = 4360000

Therefore R = √(4360000) =  2088.06 N

The direction of the force = atan (2000/600) = 73.3 ° clocwise or 106.699 ° counter clockwise

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Explanation:

Half equation:

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Overall equation

AuI3 --> 2Au + 3I2

A.

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D. Surface tension.

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Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

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0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

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