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Levart [38]
3 years ago
6

An ion with 11 protons 12 neutrons and a charge of + 1 has an atomic number of

Chemistry
1 answer:
posledela3 years ago
5 0

Answer:

11 electrons total and 23amu

Explanation:

This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu.

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Write the scientific term "A number used by Bohr in the explanation of the spectrum of hydrogen atom and designated by the symbo
In-s [12.5K]

Answer:

Quantum number

Explanation:

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3 years ago
Calculate how to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solution. show your work.
Romashka-Z-Leto [24]
250.00 mL) x (1.0 M ) / (2.5 M) = 100 mL

So take 100 mL of 2.5 M HCl and dilute it to 250 mL.
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4 years ago
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What does it mean if data are reproducible but not accurate?
egoroff_w [7]
If data results a reproducible but not accurate, it means that there was a high level of precision, but not complete accuracy.
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4 years ago
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Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t
ratelena [41]

Answer:

\Delta G^0 _{rxn} = 207.6\ kJ/mol

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

\Delta G_f^0  \ \ \ N_2O_{(g)} = 103 .8  \ kJ/mol

\Delta G_f^0  \ \ \ N_2{(g)} =0 \ kJ/mol

\Delta G_f^0  \ \ \ O_2{(g)} =0 \ kJ/mol

\Delta G^0 _{rxn} = 2 \times \Delta G_f^0  \ N_2O_{(g)} - ( 2 \times  \Delta G_f^0  \ N_2{(g)} +   \Delta G_f^0  \ O_{2(g)})

\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times  0 +   0)

\Delta G^0 _{rxn} = 207.6\ kJ/mol

The equilibrium constant determined from the partial pressure denoted as K_p can be expressed as :

K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}

K_p = \dfrac{1}{ (22.20)}

K_p = 0.045

\Delta G = \Delta G^0 _{rxn} + RT \ lnK

where;

R = gas constant = 8.314 × 10⁻³ kJ

\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15  \ ln(0.045)

\Delta G =207.6 + 2.4788191 \times \ ln(0.045)

\Delta G =207.6+ (-7.687048037)

\Delta G = 199.912952  kJ

ΔG ≅ 199.91 kJ

7 0
4 years ago
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: ()Na2
anyanavicka [17]

Answer:

The coefficients in order are 2, 1, 1

Explanation:

Each side of the reaction needs to have the same number of each element due to conservation of matter.

First I looked at what was uneven, notice there are 2 Na on the left side and 4 Na on the left. The easiest way to fix that is to add a 2 on the Na2HPO4:

2(Na2HPO4)--> Na4P2O7 + H2O

Next take count of each element on both sides to see if the 2 balanced everything:

On the left there are 4 Na, 2 H, 2 P, and 8 O

On the right there are 4 Na, 2 H, 2 P, and 8 O

Since both sides match, you are done!

7 0
3 years ago
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