Answer correctly please

When fossil fuels are burned, they release energy stored years ago. true or false

Mariulka [41]

Answer:true

Explanation:

5 0

3 years ago

What happens when you mix baking powder baking soda and hydrogen peroxide together?

katen-ka-za [31]

Its just like backing soda and viniger i think hope that helped

8 0

3 years ago

Which has a different number of neutrons from protons

MA_775_DIABLO [31]

I’m not sure but it has to be hydrogen

6 0

4 years ago

How many gallons of concentrated sulfuric acid (density of 1.84 g/cm3) are required to have a mass of 184.33 pounds?

KengaRu [80]

After series of conversion from one unit to another, the number of gallons was found to be 12 litres

<h3>Density, Mass and Volume</h3>

Given Data

Density of Sulfuric acid = 1.84 g/cm3

Mass of Sulfuric acid = 184.33 Pounds

Conversion from pounds to Gram

1 kg ---------2.204 lb

x kg ---------184.33 lb

x = 184.33/2.204

x = 83.634 kg

hence the mass in gram = 83.634*1000

mass in gram = 83634 g

Now let us find the volume

We know that density = mass/volume

volume = mass/density

volume = 83634/1.84

volume = 45453.26 cm^3

Convert cm^3 to litres

Volume in litres = 45453.26 /1000

Volume in litres = 45.45 Litres

Convert from Litres to Gallons

1 gallon = 3.79 L

x gallons = 45.45 L

x = 45.45/3.79

x gallons = 11.99 L

Approx = 12 Litres

Learn more about density here:

brainly.com/question/1354972

7 0

2 years ago

Calculate by (a)% weight and (b) %mole each of the elements present in sugar

Musya8 [376]

Explanation:

Molecular mass of sugar = $C_{12}H_{22}O_{11}$ : = 432 g/mol

Atomic mass of carbon atom = 12 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Atomic mass of oxygen atom = 16 g/mol

a) Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100$

Percentage of carbon by weight in $C_{12}H_{22}O_{11}$ :

$\frac{12\times 12 g/mol}{342 g/mol}\times 100=42.10\%$

Percentage of hydrogen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{22\times 1g/mol}{342 g/mol}\times 100=6.43\%$

Percentage of oxygen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{11\times 16g/mol}{342 g/mol}\times 100=51.46\%$

b) Percentage of mole each of the elements present in sugar:

= $\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}\times 100$

In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

Percentage of carbon by mole in $C_{12}H_{22}O_{11}$ :

$\frac{12 mol}{45 mol}\times 100=26.66\%$

Percentage of hydrogen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{22 mol}{45 mol}\times 100=48.88\%$

Percentage of oxygen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{11 mol}{45 mol}\times 100=24.44\%$

7 0

4 years ago