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shtirl [24]
3 years ago
9

How many atoms are in Cu3(PO4)2

Physics
2 answers:
nasty-shy [4]3 years ago
8 0
3Cu + 2P + 4×2 O
=13 atoms
anastassius [24]3 years ago
5 0
The answer is 24 atoms
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David is running laps around his apartment complex. Each lap is 1000 m. Starting from his front door and ending at his front doo
adelina 88 [10]

Answer:

Displacement = 4000 m

Explanation:

Given that,

Each lap is 1000 m.

David completes 4 laps of his complex

We need to find David's displacement. In n laps, the net displacement is n time of distance covered.

Displacement = 4 × 1000

= 4000 m

Hence, Davis's displacement is 4000 m.

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3 years ago
How do you inhibitors work
bonufazy [111]

Answer:

By binding to enzymes' active sites, inhibitors reduce the compatibility of substrate and enzyme and this leads to the inhibition of Enzyme-Substrate complexes' formation, preventing the catalyzation of reactions and decreasing (at times to zero) the amount of product produced by a reaction.

Explanation:

6 0
4 years ago
Find the force in free space between two like point charges of one coulomb each placed one metre apart
Umnica [9.8K]

Explanation:

{ \rm{force =  \frac{q _{1}q _{2} }{4\pi \phi \:   {r}^{2} } }} \\

  • q is charge
  • 4πQ is 1 / (9 × 10^9)
  • r is separation distance

{ \rm{force =  \frac{1 \times 1 \times 9 \times  {10}^{9} }{ {1}^{2} } }} \\  \\ { \boxed{ \rm{force = 9 \times  {10}^{9} \: newtons }}}

3 0
3 years ago
Draw the model of an atom with an atomic number of 7 and a mass number of 15. How many valence electrons are in this atom.
o-na [289]

Answer:

There are 5 valence electrons

Explanation:

Valence electrons are electrons found in the outermost shell of an atom.

7 0
3 years ago
A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
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