6 i belive let me double check
It would be C as the answers
Answer:
A' (11, 4), B' (-10, -6), C' (7, -9)
Step-by-step explanation:
Since you are reflecting over the y-axis, you take the opposite of the x value. So if the x is positive, make it negative. If the x is negative, make it positive. The y coordinate stays the same.
7:8 Purl Stitches I believe ! :)
Answer:
<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>
Step-by-step explanation:
Given the expression 
To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

Then we find the LCM of the resulting function

The final expression gives the required answer