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VladimirAG [237]
3 years ago
6

suppose you and your friend are on the moon. will you be able to hear any sound produced by your friend?

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

No, on the moon no medium sound can travel, astronauts communicate using signs and microphones.

Explanation:

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Two bulbs marked 200 W-250 V and 100 W-250 V are joined in
lozanna [386]

Answer:

<em>P = 66.67 W</em>

Explanation:

<u>Joule Heating</u>

It's the process by which the electric current passing through a conductor produces heat.

Also known as Joule's first law or the Joule–Lenz law, states that the power of heating generated by an electrical conductor (P) is proportional to the product of its resistance (R) and the square of the current (I).

It can be described by the equation that follows:

P = I^2.R

Also, we can calculate the voltage V with the formula of Ohm's law:

V = I.R

Combining both equations, power can be related to the voltage:

\displaystyle P=\frac{V^2}{R}

Given the power and the voltage, the resistance can be calculated by solving for R:

\displaystyle R=\frac{V^2}{P}

There are two bulbs marked P=200W V=250V and P=100 W V=250.

The first bulb has a resistance of:

\displaystyle R_1=\frac{250^2}{200}

\displaystyle R_1=312.5\Omega

The first bulb has a resistance of:

\displaystyle R_2=\frac{250^2}{100}

\displaystyle R_1=625\Omega

When connected in series, the total resistance is

R = R_1 + R_2=312.5\Omega+625\Omega

R=937.5\Omega

The total power consumed when connecting them to a V=250 V supply is:

\displaystyle P=\frac{250^2}{937.5}

P = 66.67 W

4 0
3 years ago
Please answer this fast <br>I 'll marks them brainliest answer <br>​
Reptile [31]

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

8 0
3 years ago
A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
KATRIN_1 [288]

Complete Question

Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?

Answer:

The value  is  T_R  = 11.8 \  days  

Explanation:

From the question we are told that

   The semi - major axis of the rocky debris  a_R = 45.0\  AU

   The semi - major axis of  Planet D is  a_D  = 60 \  AU

    The orbital  period of planet D is  T_D = 18.164 \  days

Generally from Kepler third law

          T \  \ \alpha \ \ a^{\frac{3}{2} }

Here T is the  orbital period  while a is the semi major axis

So  

        \frac{T_D}{T_R}  =  \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}

=>     T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }  

=>     T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }

=>      T_R  = 11.8 \  days  

   

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tangare [24]
Nah gaya seperti titik fashion seperti apa yang Anda mana dan hal-hal seperti itu. (tell me if you cant understand)
8 0
3 years ago
Read 2 more answers
How are the magnets able to have zero resistance
Levart [38]

they are heated to extremely high temperatures. they are cooled to extremely low temperatures. they are made to be very thick.

5 0
3 years ago
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