Question

What mass of zinc is needed to react with 23.1g of phosphoric acid according to the following equation?

Answer 1

23.01 g of zinc (Zn)

Explanation:

We have the following chemical reaction:

3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂

number of moles = mass / molar weight

number of moles of phosphoric acid = 23.1 / 98 = 0.236 moles

Taking in account the chemical reaction, we devise the following reasoning:

if           2 moles of H₃PO₄ are reacting with 3 moles of Zn

then      0.236 moles of H₃PO₄ are reacting with X moles of Zn

X = (0.236 × 3) / 2 = 0.354 moles of Zn

mass = number of moles × molar weight

mass of Zn = 0.354 × 65 = 23.01 g

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