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Explanation:
Ionization equation for is as follows.
s s s
Now, the expression for the solubility product is as follows.
=
=
As the concentration of is given as 0.4 M.
So, = 0.4 M
Putting the given values as follows.
= 12.325 \times 10^{-5}[/tex]
Hence, the solubility of in
is
.
Therefore, solubility of in g/ml as follows.
= 0.0167 g/L
Thus, we can conclude that solubility of is 0.0167 g/L.