The type of pollution when small particles of soil are suspended in the water is called Suspended Matter Pollution. <span>This type of pollution happens when soil enter the water and do not mix in with the water molecules.</span>
Its B polaris seems smaller than the Sun
Answer:
k = 1 700.7 N/m
v0 = 9.8 m/s^2
Explanation:
Hello!
We can answer this question using conservation of energy.
The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.
When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.
PS = (1/2) k x^2 <em>where x is the compresion or elongation of the spring</em>
PG = mgh
a)
Since energy must be conserved and we are neglecting any energy loss:
PS = PG
Solving for k
k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)
k = 1 700.7 N/m
b)
Since the potential energy of the spring transfors to kinetic energy of the ball we have that:
PS = KE
that is:
(1/2) k x^2 = (1/2) m v0^2
Solving for v0
v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)
v0 = 9.8 m/s^2
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity 
.
The cross-sectional area of the of a wire is given by;
where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;
Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;
Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;
Given;
We then use equation (1) to fine the ratio of the area 
to 
bearing in mind that 
This ratio gives 0.8281. Substituting this into equation (5), we get the following;
