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3 years ago

You are riding in an elevator on the way to the

Physics

1 answer:

timofeeve [1]3 years ago

4 0

Answer:

F = 104.832 N

Explanation:

given,

upward acceleration of the lift = 1.90 m/s²

mass of box containing new computer = 28 kg.

coefficient of friction = 0.32

magnitude of force = ?

box is moving at constant speed hence acceleration will be zero.

Now force acting due to lift moving upward =

F = μ m ( g + a )

F = 0.32 × 28 × ( 9.8 + 1.9 )

F = 104.832 N

hence, the force applied should be equal to 104.832 N

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The answer to number 9 please

Delicious77 [7]

The magnitude is doubled. The direction doesn't change.

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3 years ago

1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa

WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

$W= mg$

$m = \dfrac{W}{g}$

Put the value into the formula

$m=\dfrac{81.34}{9.8}$

$m=8.3\ kg$

The mass per unit length of the wire

$m_{l}=\dfrac{m}{l}$

Put the value into the formula

$m_{l}=\dfrac{8.3}{10000}$

$m_{l}=8.3\times10^{-4}\ kg/m$

We need to calculate the frequency in the wire

Using formula of frequency

$f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}$

Put the value into the formula

$f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}$

$f_{w}=189.62\ Hz$

We need to calculate the beat frequency

Using formula of beat frequency

$f_{b}=f_{in}-f_{w}$

Put the value into the formula

$f_{b}=196-189.622$

$f_{b}=6.378\ Hz$

Hence, The beat frequency is 6.378 Hz.

5 0

3 years ago

A 3,162-kg truck moving with a velocity of 12 m/s to the East hits a 510-kg parked car. The impact causes the car to be set in m

Musya8 [376]

Given:

The mass of the truck is m1 = 3162 kg

The speed of the truck is v1i = 12 m/s in East

The mass of the parked car is m2 = 510 kg

The speed of car is v2i = 0 m/s

The speed of car after collision is v2f = 24 m/s in East

To find the speed of the truck after collision.

Explanation:

The final velocity of the truck will be

$\begin{gathered} m1v1i+m2v2i=m1v1f+m2v2f \\ v1f\text{ =}\frac{m1v1i-m2v2f+m2v2i}{m1} \\ =\frac{3162\times12-510\times24+510\times0}{3162} \\ =8.129\text{ m/s} \end{gathered}$

Thus, the speed of the truck after collision is 8.129 m/s

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1 year ago

What carries an electric current through a solution?

sashaice [31]

Free ions. Negative ions have one extra electron, positive ions are missing an electron. Negative ions give up their extra electron easily. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions.

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3 years ago

Can solar energy turn into sunlight?

iragen [17]

Nothing has to turn.

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