You are riding in an elevator on the way to the

Physics

1 answer:

timofeeve [1]3 years ago

4 0

Answer:

F = 104.832 N

Explanation:

given,

upward acceleration of the lift = 1.90 m/s²

mass of box containing new computer = 28 kg.

coefficient of friction = 0.32

magnitude of force = ?

box is moving at constant speed hence acceleration will be zero.

Now force acting due to lift moving upward =

F = μ m ( g + a )

F = 0.32 × 28 × ( 9.8 + 1.9 )

F = 104.832 N

hence, the force applied should be equal to 104.832 N

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