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3 years ago

¿Qué distancia recorre un móvil que lleva una aceleración de 5m/s durante 10seg?

Physics

1 answer:

coldgirl [10]3 years ago

3 0

Answer:

250 m

Explanation:

The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

Assuming the car starts from rest,

u = 0

Also we know that

a = 5 m/s^2 (acceleration of the car)

t = 10 s

Substituting, we find the distance covered:

$s=0+\frac{1}{2}(5)(10)^2=250 m$

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The left side of the heart creates a pressure of 120 mm Hg by exerting a force directly on the blood over an effective area of 1

jeka57 [31]

Answer:

23.99N

Explanation:

Given:

Pressure created by the heart = 120mm of hg

converting the pressure into the standard unit of N/m²

1mm of hg = $\frac{1}{760}atm=\frac{1}{760}\times 1.013\times10^5N/m^2$

now, 120 mm of hg in N/m² will be

120mm of hg = $\frac{12}{760}\times 1.013\times10^5N/m^2$

also

given effective area = 15.0 cm² = 15 × 10⁻⁴m²

Now,

Force = Pressure × Area

thus,

Force exerted will be = $\frac{120}{760}\times 1.013\times10^5N/m^2$ × 15 × 10⁻⁴m²

Force exerted will be = 23.99N

4 0

3 years ago

Read 2 more answers

A gymnast spring vertical upward from a trampoline as in figure. The gymnast leaves the trampoline at height of 1.20m and reache

vaieri [72.5K]

Answer:

The initial velocity of the gymnast is 8.5 m/s.

Explanation:

We can use the kinematic equation

$v_f^2= v_o^2+2ad$

to figure out the initial velocity $v_o$ of the gymnast.

Now, when the gymnast reaches the maximum height, the distance he has traveled is $d = 4.8m- 1.2m = 3.6 m$ , and his velocity is zero; therefore $v_f =0$ .

Thus, we have

$0 = v_0^2+2(-10m/s^2)(3.6m)$

$v_0^2=72m^2/s^2$

$\boxed{v_0= 8.5m/s}$

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3 years ago

The behaviors that light exhibits are reflection, refraction, diffraction, polarization, and dispersion. Answer

Molodets [167]

I believe the correct answer is false. The behaviors that light exhibits are reflection, refraction, diffraction but not polarization, and dispersion. Light behaves as a wave - it undergoes reflection, refraction, and diffraction just like any wave would. Hope this answers the question.

5 0

4 years ago

HELP what is the answer to this question?

Dennis_Churaev [7]

I think it’s c sorry if wrong

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3 years ago

What is the word for the definition of an electron in the highest occupied energy level of an atom

Oliga [24]

Answer: The word for the definition of an electron in the highest occupied energy level of an atom is " valence electron".

Explanation:

A valence electron is an external shell electron associated with an atom in chemistry and physics that can participate in the creation of a chemical bond if the highest occupied energy level of an atom is not closed. All atoms in a single covalent bond add one valence electron to form a mutual pair.

The periodic table showcases the arrangement of valence electrons group and block wise like:

Alkali metals have n s 1 as external shell configuration like H, Li, Na, K etc.
Alkaline metals have n s 2 as external hell configuration like Be, Mg, Ca etc.
p-block comprises group 13 to 18 having general electronic configuration n s 2, n p 1–6.
d-block or transition metals have general electronic configuration (n-1) d 1–10, n s 1–2.

f-block or inner transition metals have general electronic configuration (n-2) f^1–14 (n-1) d^0-1 n s^2.

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3 years ago