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Serggg [28]
3 years ago
9

In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch

loride is available. How much of the stock solution is needed
Chemistry
1 answer:
LekaFEV [45]3 years ago
8 0

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

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What is the volume of a 25 g object with a density of 9.1 g/mL? please help me​
Westkost [7]

Answer:

<h3>The answer is 2.75 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question we have

volume =  \frac{25}{9.1}   \\  = 2.747252...

We have the final answer as

<h3>2.75 mL</h3>

Hope this helps you

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Jobisdone [24]

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Henry Moseley.

Explanation:

Hello,

Henry Moseley's work stated that it is better to organize the periodic table in the light of the atomic number (which accounts for the amount of protons and electrons) instead of the atomic mass, because atomic numbers are not arbitrarily assigned as long as they have the aforesaid physical basis.

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For the 100 plane of the Miller indices the intercepts are a, ∞, ∞ or 2a, ∞, ∞.

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