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blsea [12.9K]
3 years ago
15

a given sample of a gas has a volume of 3.0 L at a pressure of 4.0 atm. If the temperature remains constant and the pressure is

changed to 6.0 atm, what is the new volume?
Chemistry
1 answer:
TEA [102]3 years ago
6 0
According to boyle p1v1=p2v2
So 3*4=6*x so x=2
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kupik [55]
Answer is :c) Gas(hydrogen sulfide)
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3 years ago
The weights of all elements are always compared to oxygen.
marishachu [46]

Answer:

The weights of all elements are always compared to the Carbon-12.

Explanation:

The weights of all elements are always compared to the Carbon-12 because the mass of carbon is 12 which is the exactly the sum of protons and neutrons.  

Oxygen was also considered the standard for some time but later this stander was rejected because in natural O¹⁷ and O¹⁸ were also present and this create the two different atomic mass tables.

AMU:

Atomic mass unit is define as the 1/12 the mass of an atom of carbon-12.

C12 has six neutron and six protons in the nucleus.

This unit is used to express the masses of atoms. We know that masses of atoms are very small and we do not have any such type of balance that can measure very small quantity. So that is way we use this scale to measure small quantity. For example, according to this scale

relative atomic mass of hydrogen is 1.008 amu

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7 0
3 years ago
What did Rutherford's gold-foil experiment help him conclude?
Svetach [21]
C. mass is protons and neutrons. Both are in the nucleus
8 0
3 years ago
Read 2 more answers
J. A gas has a volume of 12 L at 200°C with 6.0 atm.
White raven [17]

Gay Lussac's Law

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Convert:

200°C = 200 + 273 = 473 K

50°C = 50 + 273 = 323 K

Input the value:

\tt \dfrac{6}{473}=\dfrac{P_2}{323}\\\\P_2=4.097~atm

4 0
2 years ago
Read 2 more answers
Question 1 (2 points)
bogdanovich [222]

Answer:

3.75 L

Explanation:

We can solve this problem by using <em>Charles' law</em>, which states:

  • V₁T₂=V₂T₁

Where subscript 1 stands for initial volume and temperature and subscript 2 for final volume and temperature, meaning that in this case:

  • V₁ = 2.5 L
  • T₂ = 300 K
  • V₂ = ?
  • T₁ = 200 K

We <u>input the data</u>:

  • 2.5 L * 300 K = V₂ * 200 K

And <u>solve for V₂</u>:

  • V₂ =  3.75 L
5 0
3 years ago
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