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Ainat [17]
3 years ago
14

Watt which is a unit of power is equal to

Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

A joule divided by a second

Explanation:

i googled it m8 wasnt that hard to find

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A hot air balloon contains 85,000 moles of air. To what temperature must the
Oksi-84 [34.3K]

Answer:

B is the best answer for this question

8 0
3 years ago
Change in v= 9.8 m/s2xt. The diagram shows a ball falling toward Earth in<br> a vacuum.
Tresset [83]

Answer:

Option A. 39.2 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 4 s

Final velocity (v) =?

v = u + gt

Since the initial velocity (u) is 0, the above equation becomes:

v = gt

Thus, inputting the value of g and t, we can obtain the value of v as shown below:

v = 9.8 × 4

v = 39.2 m/s

Therefore, the velocity of the ball at 4 s is 39.2 m/s.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Harman [31]

The wind direction changed from morning to night because  land and water absorbing solar energy unequally.

<h3>Convection current</h3>

Convection is said to occur when there is heat transfer by an actual movement of participles from place to place. The movement of air mass (wind) is affected by the relative amounts of solar energy absorbed by the land and sea.

Hence, the wind direction changed from morning to night because  land and water absorbing solar energy unequally.

Learn more about convection current: brainly.com/question/12841408

3 0
2 years ago
NASA scientists suggest using rotating cylindrical spacecraft to replicate gravity while in a weightless environment. Consider s
dusya [7]

Answer:

Explanation:

Given

diameter of spacecraft d=148\ m

radius r=74\ m

Force of gravity F_g=mg

where m =mass of object

g=acceleration due to  gravity on earth

Suppose v is the speed at which spacecraft is rotating so a net centripetal  acceleration is acting on spacecraft which is given by

F_c=\frac{mv^2}{r}

F_c=F_g

\frac{mv^2}{r}=mg

\frac{v^2}{r}=g

v=\sqrt{gr}

v=\sqrt{1450.4}

v=38.08\ m/s    

8 0
3 years ago
Where do the electrons that form the auroras enter the magnetosphere? a. Through holes c. At the equator b. Between the magnetic
marta [7]
I think the answer is d. In the magnetotail. I hope this helps! :)
7 0
3 years ago
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