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ioda
3 years ago
6

A 0.0600-kilogram ball traveling at 60.0 meters

Physics
1 answer:
Vikki [24]3 years ago
7 0
     The momentum of ball is given by:

\Delta Q=mv \\ \Delta Q=6*10^{-2}*60 \\ \Delta Q=3.6kg*m/s
  
     Since both have the same momentum, we have:

\Delta Q=MV \\ 3.6=10^{-2}V \\ \boxed {V=360m/s}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.    

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6 0
3 years ago
it is determined that a certain light wave has a wavelength of 3.012x10^-12 m. the light travels at 2.99x10^8 m/s. what is the f
Dahasolnce [82]

Answer:

9.93\times 10^{19}Hz

Explanation:

Speed of light is the product of its wavelength and frequency, expressed as

S=fw

Where s represent speed, f is frequency while w is wavelength

Making f the subject of the formula then

f=s/w

Substituting 2.99x10^8 m/s for s and 3.012x10^-12 m for w then

f=\frac {2.99\times 10^{8}}{3.012\times 10^{-12}}=9.926958831341\times 10^{19}\\f\approx 9.93\times 10^{19}Hz

Therefore, the frequency equals to 9.93\times 10^{19}Hz

4 0
3 years ago
In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.
denis23 [38]
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5 0
4 years ago
A body travel according to the law x(t)=2t+3t3 calculate the accelaration of body at t=2s
faust18 [17]

Answer:

28m/s

Explanation:

Given law,

⇒ x(t) = 2t + 3t³

Where, t = 2s

Then,

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⇒ 4 + 3(8)

⇒ 4 + 24

⇒ 28 m/s

Acceleration is 28m/s

4 0
3 years ago
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