1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
3 years ago
5

If a sled is being pulling on the ground toward the right with a force of 100 N and friction is acting on it to the left with a

force of 85 N, what is the net force
of the sled?
O 15 N to the left
15 N to the right
185 N to the right
185 N to the left
Physics
1 answer:
Korolek [52]3 years ago
5 0

Answer:

15 N to the right.

Explanation:

100 N to the right -->

85 N to the left <--

So therefore in order to find the net force of where the sled is being dragged towards is 100 N - 85 N = 15 N.

So the sled is moving towards the right of 15 N.

You might be interested in
Check all of the following statements that describe velocity.
Nata [24]

Answer:

Choices A, B, and C are correct.

Explanation:

Let us look at each of the choices one by one:

A. It is a vector

Yes. Velocity is a vector, or it's a speed with direction.

B. It is the change in displacement divided by the change in time.

Yes. The velocity can be written as

v = \dfrac{\Delta\bold{x}}{\Delta t}

where \bold{x} is the displacement—a vector quantity.

C. It can be measured in meters per second.

Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.

D. It is the slope of the acceleration vs. time graph.

Nope. The velocity is the slope of displacement vs. time graph.

Hence, only choices A, B, and C are correct.

4 0
4 years ago
How is a ecosysten different from a community​
Komok [63]
An ecosystem is the diversity of many communities of organisms where they interact with living as well as non living thing whereas community contains the variety of populations of different species. Hope this helps x
5 0
3 years ago
Read 2 more answers
A 4.00kg counterweight is attached to a light cord, which is would around a spool. The spool is a uniform solid cylinder of radi
Sergio [31]

Answer:

Explanation:

Given that,

Mass of counterweight m= 4kg

Radius of spool cylinder

R = 8cm = 0.08m

Mass of spool

M = 2kg

The system about the axle of the pulley is under the torque applied by the cord. At rest, the tension in the cord is balanced by the counterweight T = mg. If we choose the rotation axle towards a certain ~z, we should have:

Then we have,

τ(net) = R~ × T~

τ(net) = R~•i × mg•j

τ(net) = Rmg• k

τ(net) = 0.08 ×4 × 9.81

τ(net) = 3.139 Nm •k

The magnitude of the net torque is 3.139Nm

b. Taking into account rotation of the pulley and translation of the counterweight, the total angular momentum of the system is:

L~ = R~ × m~v + I~ω

L = mRv + MR v

L = (m + M)Rv

L = (4 + 2) × 0.08

L = 0.48 Kg.m

C. τ =dL/dt

mgR = (M + m)R dv/ dt

mgR = (M + m)R • a

a =mg/(m + M)

a =(4 × 9.81)/(4+2)

a = 6.54 m/s

6 0
4 years ago
Read 2 more answers
A man walks 30m to the west, then 5m to the east in 45 seconds. What is the average velocity?
solong [7]
1.28m/s the velocity is found by distance/time.
8 0
4 years ago
Read 2 more answers
A 2 kg rock is at the edge of a cliff 20 meters above a lake The rock becomes loose and falls toward the water below. Calculate
natima [27]

Answer:

The potential energy (P.E) at the top is 392 J

The kinetic energy (K.E) at the top is 0 J

The potential energy (P.E) at the halfway point is 196 J.

The kinetic energy (K.E) at the halfway point is 196 J.

Explanation:

Given;

mass of the rock, m = 2 kg

height of the cliff, h = 20 m

speed of the rock at the halfway point, v = 14 m/s

The potential energy (P.E) and kinetic energy (K.E) when its at the top;

P.E = mgh

P.E = (2)(9.8)(20)

P.E= 392 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the top of the cliff = 0

K.E = ¹/₂(2)(0)²

K.E = 0

The potential energy (P.E) and kinetic energy (K.E) at the halfway point;

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the halfway point = 14 m/s

K.E = ¹/₂(2)(14)²

K.E = 196 J.

4 0
3 years ago
Other questions:
  • Calculate the standard electrode potential difference (e°) of the daniell cell (at 1 bar) if temperature is 473.15 k.
    14·1 answer
  • Select the properties that apply to superconductors.
    14·2 answers
  • Suppose you first walk 12.0 m in a direction 20? west of north and then 20.0 m in a direction 40.0? south of west. how far are y
    15·1 answer
  • Which statement accurately describes a similarity between Earth and Venus?
    5·1 answer
  • What happens when humans change the flow of water?
    13·2 answers
  • You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
    6·1 answer
  • Discuss potential behavioral concerns for people should they travel to Mars
    6·1 answer
  • A gymnast jumps directly up onto a beam that is 1.5 m high. From the beam, she jumps 0.5 m straight up and lands back on the bea
    13·1 answer
  • Describe the octet rule in terms of noble-gas configurations and potential energy
    12·2 answers
  • One Affective way to develop the feeling function in one’s personality is to
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!