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emmainna [20.7K]
4 years ago
12

Two equal-mass pieces of metal are sitting side by side at the bottom of a deep lake. One piece is aluminum and the other is lea

d.
Part A
Which piece has the greater buoyant force acting on it?

A. the aluminum
B. the lead
C. They both have the same buoyant force acting on them.
Physics
1 answer:
murzikaleks [220]4 years ago
5 0

Answer:

A. Aluminium

Explanation:

Buoyant force is  simple terms refers to the weight of water displaced when an object is immersed in it. The higher the volume of an object, the higher the buoyant force.

From the problem, we have two metals of equal mass, aluminium and lead, of which lead is denser.

density =\frac{mass}{volume}

Volume =\frac{mass}{density}

This means that the volume of each metal depends on the density, and for the fact that lead is denser , it will have a lower volume than aluminium which means Aluminium will have a greater buoyant force.

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September 9 and 24 represent spring tides due to the added gravitational pull of the Sun.

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4 years ago
A Carnot engine operates with an efficiency of 26.0% when the temperature of its cold reservoir is 281 K. Assuming that the temp
VLD [36.1K]

Answer:

The temperature of cold reservoir should be 246.818 K for efficiency of 35%

Explanation:

In first case we have given efficiency of Carnot engine = 26 % = 0.26

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We know that efficiency of Carnot engine is given by

\eta =1-\frac{T_L}{T_H}

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And temperature of hot reservoir is same so T_H=379.72K

So 0.35=1-\frac{T_L}{379.72}

T_L=246.818K

So the temperature of cold reservoir should be 246.818 K for efficiency of 35%

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An electric current in a conductor varies with time according to the expression I(t) = 100 sin (120πt) , where I is in amperes a
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The  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

<h3>Total charge through a conductor</h3>

A conductor is a substance that allow current and electricity to pass through it.

The expression that will be used to calculate the current is expressed s:

I(t) = 100 sin (120πt)

where

I is in amperes and t is in seconds.

Since dQ = Idt =  I(t) = 100 sin (120πt)

On integrating

Q = 100*120πcos(120πt) |¹/¹²⁴⁰₀

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Hence the  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

Learn more on total charge through a conductor here: brainly.com/question/15083960

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