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dimaraw [331]
3 years ago
5

Use the drop-down menu to complete the statement. This is why they have similar Atoms of elements in the same group have the sam

e number of chemical properties. ​
Chemistry
1 answer:
ivann1987 [24]3 years ago
3 0
Periodic table? I don’t really know what you’re options are since there is no picture of the drop down or anything. If you can tell me what the options are, then I can answer more accurately. What you’re describing right now is the periodic table.
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The harmonic law would suggest that Neptune will take how much time to orbit the Sun than Mercury?
Delicious77 [7]
The harmonic law would suggest that Neptune will take a longer amount of time to orbit the sun than Mercury. That's what I think anyways
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3 years ago
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Which of the following is an example of a chemical change?
Vsevolod [243]

Answer:

D

Explanation:

It is D because once youve put together the ingredients and baked it you can not go in and taake out every ingredient and put it back to how it was before (Please also try to help me with my question it it about scaled copies, Please and thank you!)

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3 years ago
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Jason ran 5/7 of the distance around the school track sara ran 4/5 of Jason distance what fraction of the total distance around
FrozenT [24]
Let x represent the total distance around the track
Jason's distance: (5/7)x
Sara ran (4/5) of Jason's distance,
so she ran (4/5)*(5/7)x = (4/7)x
Sara ran 4/7 of the total distance
7 0
3 years ago
I have no idea what to do please help me quickly!
Irina18 [472]

Answer:

The farther away the planet the slower the revolution around the earth. the closer the faster.

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its like a tetherball pole when it wraps around it gets closer and spins faster and faster untill it stops. Brainliest?

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3 years ago
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Calculate the enthalpy of the reaction below (∆Hrxn, in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g).
nalin [4]

The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE  for C≡O  = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

To learn more about enthalpy here

brainly.com/question/13981382

#SPJ1

7 0
1 year ago
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