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3 years ago

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics

2 answers:

Paha777 [63]3 years ago

6 0

Light sound and thermal

drek231 [11]3 years ago

6 0

D.) <span>light, sound, and thermal

Hope this helps!</span>

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A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second 2. What is the net force on the car?

Elodia [21]

Newton #2: F = M a

(1 x 10³ kg) (4.5 m/s²) = 4,500 newtons

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3 years ago

A _____ resource could run out thousands of years from now.

tresset_1 [31]

The answer is B. Nonrenewable

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3 years ago

A proton, traveling with a velocity of 4.6 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.0

Kobotan [32]

Answer:

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

Explanation:

Force on moving charge in magnetic field is given as

$F = q(\vec v \times \vec B)$

here we know this is force on proton

so we have

$q = 1.6 \times 10^{-19} C$

$F = 6.0 \times 10^{-14} (-\hat j) N$

also we know that the velocity of charge is

$v = 4.6 \times 10^6 \hat i m/s$

now from above formula we have

$(6.0 \times 10^{-14}) = (1.6 \times 10^{-19})(4.6 \times 10^6)B$

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

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4 years ago

A 22.0 kg bucket of concrete is connected over a very light frictionless pulley to a 375 N box on the roof of a building as show

Veronika [31]

Answer:

vf = 3.27[m/s]

Explanation:

In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.

With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.

With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.

Then we equalize the two stress equations and we can clear the acceleration.

a = 3.58 [m/s^2]

As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.

$x = \frac{1}{2} *a*t^{2}\\1.5 = \frac{1}{2}*(3.58) *t^{2} \\t = 0.91 [s]$