Question

What change should be expected in the velocity of a body to maintain the same

Answer 1

Answer:

firstly,

ke=1÷2mv^2

on putting same ke by increasing mass by 16 times new velocity becomes v'

then

ke=1÷2×16m×v'^2

from above we can write

1÷2mv^2=1÷2×16m×v'^2

v^2=16v'^2

1÷4v=v'

hence original velocity should be decreased by 4 times to keep same ke