The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
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Answer:
Ф = 142.674 degree
Ф = 2.490131057 rad
wavelength = 0.396316 λ
Explanation:
Given data
combined wave having an amplitude 0.64 times
to find out
answer in degrees, radians, and fraction of the wavelength
solution
let us consider these two wave equation
Asin(ωt) and the Asin (ωt + Ф)
and here Ф is phase difference
so we say
resultant wave is
Y = Asin(ωt) + Asin (ωt + Ф) = Asin(ωt + Ф/2) cos ( Ф/2)
so Y = A' sin(ωt + Ф/2)
we know that here resultant wave amplitude is 2A cos ( Ф/2)
so
put A= 0.64 A
so 2Acos ( Ф/2) = 0.64 A
and Ф/2 = 71.3370
Ф = 142.674 degree
Ф = 2.490131057 rad
so wavelength is 2.490131057 / 2π
wavelength = 0.396316 λ
Answer:
0.08 ampere
Explanation:
Power = voltage x current
W = v x I
Given
Power = 10.0 w
V = 120v
I = ?
Therefore
10.0 = 120 x I
Divide both sides by by 120
10.0/120 = 120/120 x I
0.08 = I
I = 0.08 ampere
Answer: I think its zero-
I dont really know about this...
Answer:
B.The force of friction between the block and surface will decrease.
Explanation:
The force of friction is given by
where is the coefficient of friction and is the normal force.
When the student pulls on the block with force at an angle , the normal force on the block becomes
and hence the frictional force becomes
.
Now, as we increase , increases which as a result decreases the normal force , which also means the frictional force decreases; Hence choice B stands true.
<em>P.S: Choice D is tempting but incorrect since the weight </em><em> is independent of the external forces on the block. </em>