A SMA wire in the un-stretched condition is then given an initial strain of εo (to preload the wire) at room temperature (RT). I
1 answer:
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Explanation:
It is given that,
Average power per unit mass generated by Lance,
(a) Distance to cover race,
Average speed of the person, v = 11 m/s
If t is the time taken to cover the race.
t = 14545.46 s
Let W is the work done. The relation between the work done and the power is given by :
W = 7090911.75 J
(b) Since,
So, in 7090911.75 J,
W = 1694.01 J
Hence, this is the required solution.
To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,
Here,
V = Voltage
I = Current
While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,
Applying Ohm's law
Therefore the equivalent resistance of the light string is