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Ulleksa [173]
2 years ago
6

A girl throws a marshmallow that lands in her friend’s mouth 2 m away. The girl threw the marshmallow at an angle of 30 degrees.

How hard did she throw the marshmallow?
Physics
1 answer:
natima [27]2 years ago
4 0

She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.

<h3>What is projectile motion?</h3>

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

Given data;

The marshmallow was thrown at a distance of 2 meters

Range,R =  3 m

Initial velocity,u

The angle at which the marshmallow was thrown,θ = 30°

The acceleration due to gravity,g = 9.81 m/s²

The projectile's motion is divided into two parts: horizontal and vertical motion.

\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R  = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec

Hence, she throws the marshmallow at a speed of 4.76 m/sec.

To learn more about the projectile motion refer to the link;

brainly.com/question/11049671

#SPJ1

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\theta = 20.98 degree

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now when temperature is changed to 313 K we have

t = 313 - 273 = 40 degree

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now from two equations we have

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so we have

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7 0
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How much heat is required to raise the temperature of 100 g of water from 5 degree celsius to 90 degree celsius?​
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Explanation:

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Answer:

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Explanation:

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applying the equation of rectilinear motion we have:

x = xo + vot + at^2/2

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6 0
3 years ago
Read 2 more answers
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