Question

A combined circuit has two resistors in parallel (10.0 ohms and 14.0 ohms) and another in series (5.0 ohms). If the power source is 9.0 volts, what is the current?
A. 1.6 amps
B. 5.8 amps
C. 0.83 amps
D. 1.3 amps

Answer 1

Thank you for posting your physics question here at brainly. To answer the question, with the power source is 9.0 volts when combined circuit has two resistors in parallel (10.0 ohms and 14.0 ohms) and another in series (5.0 ohms) is 0.83 amps. Therefore the answer is C. 

Answer 2

Answer

The current is  0.83 amps .

Option (C) is correct .

Explanation :

Formula for parallel resistors

$\frac{1}{R_{Parallel}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$

As given

A combined circuit has two resistors in parallel (10.0 ohms and 14.0 ohms)  .

$R_{1}= 10\ ohms$

$R_{2}= 14\ ohms$

Putting all the values in the above

$\frac{1}{R_{Parallel}} = \frac{1}{10} + \frac{1}{14}$

L.C.M of (10,14) = 70

$\frac{1}{R_{Parallel}} = \frac{7+5}{70}$

$\frac{1}{R_{Parallel}} = \frac{12}{70}$

$R_{Parallel} = \frac{70}{12}$

$R_{Parallel} = 5.83\ ohms\ (Approx)$

As given

Another resistors in the series is 5.0 ohms .

Formula

$R_{Total}=R_{Parallel}+ R_{3}$

$R_{Parallel}=5.83\ ohms$

$R_{3}=5\ ohms$

$R_{Total}=5.83+5$

$R_{Total}=10.83\ ohms$

Now by using the ohms law .

$I = \frac{V}{R}$

Where V is voltage , R is resistance and I is current .

As given

The power source is 9.0 volts .

V = 9 volts

$R_{Total}=10.83\ ohms$

Putting values in ohms law

$I = \frac{9}{10.83}$

I = 0.83 amps (Approx)

Therefore the current is  0.83 amps .

Option (C) is correct .