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Papessa [141]
3 years ago
14

Why are slow-twitch muscles more beneficial than fast-twitch muscles for cardiorespiratory fitness?

Physics
2 answers:
nata0808 [166]3 years ago
6 0

The answer is D. Slow-twitch muscles are able to use oxygen more efficiently than fast-twitch muscles.

Hope this helps

dlinn [17]3 years ago
4 0

Answer:D

Explanation: with fitness and running you normally run for longer distances the slow twitch mussels help with this by using less oxygen in a longer amount of time

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The energy an object has due to its motion is called kinetic energy.

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After a displacement of 17 m, a train on a straight track is at the position xf = –2.5 m
EastWind [94]

-19.5m

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3 years ago
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A negatively charged particle is moving to the right, directly above a wire have a current flowing to the right. In which direct
Varvara68 [4.7K]

Answer:

C) upward

Explanation:

The problem can be solved by using the right-hand rule.

First of all, we notice at the location of the negatively charged particle (above the wire), the magnetic field produced by the wire points out of the page (because the current is to the right, so by using the right hand, putting the thumb to the right (as the current) and wrapping the other fingers around it, we see that the direction of the field above the wire is out of the page).

Now we can apply the right hand rule to the charged particle:

- index finger: velocity of the particle, to the right

- middle finger: direction of the magnetic field, out of the page

- thumb: direction of the force, downward --> however, the charge is negative, so we must reverse the direction --> upward

Therefore, the direction of  the magnetic force is upward.

3 0
3 years ago
An aircraft performs a maneuver called an "aileron roll." During this maneuver, the plane turns like a screw as it maintains a s
Dmitriy789 [7]

Answer:

0.17724 m/s²

Explanation:

D = Diameter of roll = Length of wing = 11 m

T = Time it takes to complete the circle = 35 s

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v=\frac{2\pi R}{T}\\\Rightarrow v=\frac{\pi D}{T}\\\Rightarrow v=\frac{\pi\times 11}{35}\\\Rightarrow v=0.98735\ m/s

Acceleration

a=\frac{v^2}{R}\\\Rightarrow a=\frac{0.98735^2}{\frac{11}{2}}\\\Rightarrow a=0.17724\ m/s^2

Acceleration of the tip of the plane is 0.17724 m/s²

3 0
3 years ago
An open pipe of length 0.39 m vibrates in the third harmonic with a frequency of 1400 Hz what is the distance from the center of
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Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

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now here at the center of the pipe it will form Node

we need to find the distance of nearest antinode

So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

d = \frac{0.26}{4} = 0.065 m = 6.5 cm

So the distance will be 6.5 cm

3 0
3 years ago
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