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Lorico [155]
3 years ago
8

Which of these items is neither Liquid, nor Gas?

Physics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

Desk

Explanation:

Because a desk is solid and its neither liquid nor gas...I hope this helps

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3 m/s
zloy xaker [14]

Answer:

0.75Hz

Explanation:

Given parameters:

Speed of the wave = 3m/s

Wavelength  = 4m

Unknown:

Frequency of the wave  = ?

Solution:

The speed of a wave is given by the expression below:

     Speed  = frequency x wavelength

  Frequency  = \frac{Speed }{Wavelength}   = \frac{3}{4}    = 0.75Hz

5 0
3 years ago
Two blocks of masses 8 kg and 4.3 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them
oee [108]

Answer:

The velocity of other mass is 3.60 m/s.

Explanation:

Given that,

Mass of first block = 8 kg

mass of second block = 4.3 kg

Speed = 6.7 m/s

We need to calculate the speed of first mass

Using conservation of momentum

(m_{1}+m_{2})u=m_{1}v_{1}+m_{2}v_{2}

where, m₁ =mass of first block

m₂ =mass of second block

m₁ =mass of first block

v₂ =speed of second block

Put the value into the formula

8+4.3\times0=8\times v_{1}+4.3\times6.7

v_{1}=\dfrac{-4.3\times6.7}{8}

v_{1}=-3.60\ m/s

Negative sign represent the opposite direction of initial value.

Hence, The velocity of other mass is 3.60 m/s.

3 0
3 years ago
Which statement best describes how work and power are different? a. To find work we need to know force and distance; to find pow
weqwewe [10]
A. To find work we need to know F and S; to find power we need to know F and V
6 0
3 years ago
A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c
Assoli18 [71]

A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .

Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.

Given

time =  20 μs = 20 * 10^{-6} s

let distance to the reflecting surface be = x

total distance travelled by pulse will be  = 2x

speed = 3.0 × 10^{8} m/s

distance = speed * time

2x = 3.0 × 10^{8} * 20 * 10^{-6}

   x = 3000 m

The reflecting object would be 3000 m away

To learn more about echo here

brainly.com/question/14861578?referrer=searchResults

#SPJ4

5 0
2 years ago
A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
Veronika [31]

Answer:

A) ω = 6v/19L

B) K2/K1 = 3/19

Explanation:

Mr = Mass of rod

Mb = Mass of bullet = Mr/4

Ir = (1/3)(Mr)L²

Ib = MbRb²

Radius of rotation of bullet Rb = L/2

A) From conservation of angular momentum,

L1 = L2

(Mb)v(L/2) = (Ir+ Ib)ω2

Where Ir is moment of inertia of rod while Ib is moment of inertia of bullet.

(Mr/4)(vL/2) = [(1/3)(Mr)L² + (Mr/4)(L/2)²]ω2

(MrvL/8) = [((Mr)L²/3) + (MrL²/16)]ω2

Divide each term by Mr;

vL/8 = (L²/3 + L²/16)ω2

vL/8 = (19L²/48)ω2

Divide both sides by L to obtain;

v/8 = (19L/48)ω2

Thus;

ω2 = 48v/(19x8L) = 6v/19L

B) K1 = K1b + K1r

K1 = (1/2)(Mb)v² + Ir(w1²)

= (1/2)(Mr/4)v² + (1/3)(Mr)L²(0²)

= (1/8)(Mr)v²

K2 = (1/2)(Isys)(ω2²)

I(sys) is (Ir+ Ib). This gives us;

Isys = (19L²Mr/48)

K2 =(1/2)(19L²Mr/48)(6v/19L)²

= (1/2)(36v²Mr/(48x19)) = 3v²Mr/152

Thus, the ratio, K2/K1 =

[3v²Mr/152] / (1/8)(Mr)v² = 24/152 = 3/19

3 0
3 years ago
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