Together, two boys had 43 cents. The first boy spent 5 cents and the second boy spent 13 cents. The first boy’s remaining money
is 2/3
of the second boy’s remaining money. How much did they each have originally?
1 answer:
Hello kiddio lets figure this out!
Let x = first
<span>y = second </span>
<span>Then </span>
<span>x - 5 = remainder of first </span>
<span>y - 13 = remainder of second </span>
<span>x - 5 = 2/3(y - 13) </span>
<span>3x - 15 = 2y - 26 </span>
<span>3x - 2y = - 11................(1) </span>
<span>x + y = 43....................(2) </span>
<span>From (2) y = 43 - x..........(3) </span>
<span>Put (3) in (1) </span>
<span>3x - 2(43 - x) = - 11 </span>
<span>3x - 86 + 2x = - 11 </span>
<span>5x = 75 </span>
<span>x = 15 cents </span>
<span>y = 43 - 15 </span>
<span>= 28 cents
</span>
Have a nice day
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Answer:
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Step-by-step explanation:
Given data
Principal= $2700
Rate= 4%
Time= 5 years
Required
the final Amount A
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A=P(1+r)^t
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A=2700(1+0.04)^5
A=2700(1.04)^5
A=2700*1.216
A=$3283.2
Hence the balance in the account after 5 years is $3283.2
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