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lawyer [7]
2 years ago
5

Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

Physics
2 answers:
Anna007 [38]2 years ago
8 0

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

Leni [432]2 years ago
6 0

It is true that the atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

<u>Explanation:</u>

The atom's atomic stability is determined by the distribution of electrons in the orbital rings . Atoms with more outer shells will stay away from nucleus which is at its centre position of the atom. Any atom which loses electron from its outer most orbit makes it as a good conductor.

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docker41 [41]

Answer:

Los objetos A y C tienen cargas del mismo signo (opcion a)

Explanation:

Hay dos tipos de cargas : cargas positivas y cargas negativas.

La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:

  • La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva).
  • El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).

Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.

Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.

Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.

Por lo que podes concluir que <u><em>los objetos A y C tienen cargas del mismo signo (opcion a)</em></u>

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