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lawyer [7]
3 years ago
5

Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

Physics
2 answers:
Anna007 [38]3 years ago
8 0

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

Leni [432]3 years ago
6 0

It is true that the atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

<u>Explanation:</u>

The atom's atomic stability is determined by the distribution of electrons in the orbital rings . Atoms with more outer shells will stay away from nucleus which is at its centre position of the atom. Any atom which loses electron from its outer most orbit makes it as a good conductor.

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A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twic
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Answer: C.

Explanation:

For a parallel-plate capacitor where the distance between the plates is d.

The capacitance is:

C = e*A/d

You can see that the distance is in the denominator, then if we double the distance, the capacitance halves.

Now, the stored energy can be written as:

E = (1/2)*Q^2/C

Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:

E = (1/2)*Q^2*d/(e*A)

e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.

Then we can define:

K = (1/2)*Q^2/(e*A)

And now we can write the energy as:

E = K*d

Then the energy is proportional to the distance between the plates, this means that if we double the distance, we also double the energy.

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3 years ago
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