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3 years ago

Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

Physics

2 answers:

Anna007 [38]3 years ago

8 0

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

Leni [432]3 years ago

6 0

It is true that the atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

<u>Explanation:</u>

The atom's atomic stability is determined by the distribution of electrons in the orbital rings . Atoms with more outer shells will stay away from nucleus which is at its centre position of the atom. Any atom which loses electron from its outer most orbit makes it as a good conductor.

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A green light is submerged 2.70 m beneath the surface of a liquid with an index of refraction 1.31. What is the radius of the ci

Anettt [7]

Answer:

The radius is $r = 3.1905 \ m$

Explanation:

From the question we are told that

The distance beneath the liquid is $d = 2.70 \ m$

The refractive index of the liquid is $n_i = 1.31$

Now the critical value is mathematically represented as

$\theta = sin ^{-1} [\frac{1}{n_i} ]$

substituting values

$\theta = sin ^{-1} [\frac{1}{131} ]$

$\theta = 49.76^o$

Using SOHCAHTOA rule we have that

$tan \theta = \frac{ r}{d}$

=> $r = d * tan \theta$

substituting values

$r = 2.7 * tan (49.76)$

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3 years ago

How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?

ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

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where,

W = Work done by the gas

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ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

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3 years ago

The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el

LUCKY_DIMON [66]

Answer:

e.)At twice the distance, the strength of the field is E/4.

Explanation:

The strength of the electric field at a certain distance from a point charge is given by:

$E=k\frac{Q}{r^2}$

where

k is the Coulomb's constant

Q is the charge

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So the new electric field strength is

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