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lawyer [7]
3 years ago
5

Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

Physics
2 answers:
Anna007 [38]3 years ago
8 0

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

Leni [432]3 years ago
6 0

It is true that the atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

<u>Explanation:</u>

The atom's atomic stability is determined by the distribution of electrons in the orbital rings . Atoms with more outer shells will stay away from nucleus which is at its centre position of the atom. Any atom which loses electron from its outer most orbit makes it as a good conductor.

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3 years ago
Read 2 more answers
True or false<br> Hydrogen fuel cells generate electricity by combining hydrogen with oxygen.
adoni [48]

Answer:

The answer is: True.

Explanation:

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(Credit: Google)

7 0
3 years ago
Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

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7 0
3 years ago
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