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lawyer [7]
3 years ago
5

Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

Physics
2 answers:
Anna007 [38]3 years ago
8 0

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

Leni [432]3 years ago
6 0

It is true that the atoms with many electron shells will let go of their electrons more easily than those with fewer shells.

<u>Explanation:</u>

The atom's atomic stability is determined by the distribution of electrons in the orbital rings . Atoms with more outer shells will stay away from nucleus which is at its centre position of the atom. Any atom which loses electron from its outer most orbit makes it as a good conductor.

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Answer:

F = 2,894 N

Explanation:

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Let's replace

     F = m w² r

The radius r and the length of the rope is related

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    r = L cos tea

Let's replace

    F = m w² L cos θ

Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

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7 0
3 years ago
Spiderman, whose mass is 70.0 kg, is dangling on the free end of a 12.2-m-long rope, the other end of which is fixed to a tree l
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Answer:

U = -3978.8 J

Explanation:

The work of the gravitational force U just depends of the heigth and is calculated as:

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for calculate the alture we will use the following equation:

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Replacing data:

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h = 5.8 m

Finally U is equal to:

U = -70(9.8)(5.8)

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Answer:

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