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olga nikolaevna [1]
1 year ago
15

I have enough pure silver to coat square meters of surface area. I plan to coat a sphere and a cube. Allowing for the possibilit

y of all the silver going onto one of the solids, what dimensions should they be if the total volume of the silvered solids is to be a maximum?.
Physics
1 answer:
Nata [24]1 year ago
5 0

An object's volume is the amount of space it occupies. Cubic meters are used to measure large volumes (m3). Centimeters cubed are used to measure smaller volumes (cm3).

The design-limiting attributes must reach or exceed target values in order to deliver the desired degree of performance. Volume is a three-dimensional measurement that's used to gauge a solid shape's capacity. It implies that the volume of a closed form determines how much space it can occupy in three dimensions. The capacity of an object is measured by its volume. For instance, a cup's capacity is stated to be 100 ml if it can hold 100 ml of water in its brim. The quantity of space occupied by a three-dimensional object can also be used to describe volume.

Learn more about capacity here-

brainly.com/question/15158174

#SPJ4

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A bystander observes the musicians heading toward each other. When musician #1 is 100 m away, the intensity is 1.24 x 10-8 W/m^2
777dan777 [17]

Explanation:

Given that,

Distance 1, r = 100 m

Intensity, I_1=1.24\times 10^{-8}\ W/m^2

If distance 2, r' = 25 m

We need to find the intensity and the intensity level at 25 meters. Intensity and a distance r is given by :

I=\dfrac{P}{4\pi r^2}.........(1)

Let I' is the intensity at r'. So,

I'=\dfrac{P}{4\pi r'^2}............(2)

From equation (1) and (2) :

I'=\dfrac{Ir}{r'^2}

I'=\dfrac{1.24\times 10^{-8}\times 100}{25^2}

I'=1.98\times 10^{-9}\ W/m^2

Intensity level is given by :

dB=10\ log(\dfrac{I'}{I_o}), I_o=10^{-12}\ W/m^2

dB=10\ log(\dfrac{1.98\times 10^{-9}}{10^{-12}})

dB = 32.96 dB

Hence, this is the required solution.

7 0
3 years ago
If an object falling freely were somehow equipped with an odometer to measure the distance it travels, then the amount of distan
ioda

Answer:c

Explanation:

Given

object is falling Freely with an odometer

Suppose it falls with zero initial velocity

so distance fallen in time t is given by

h=ut+\frac{1}{2}gt^2

here u=0 and t=time taken

h=\frac{1}{2}gt^2

for t=1 s

h_1=\frac{1}{2}g

for t=2 s

h_2=\frac{1}{2}g(2)^2=\frac{4}{2}g=2g

distance traveled in 2 nd sec=2g-\frac{1}{2}g=\frac{3}{2}g

for t=3 s

h_3=\frac{1}{2}g(3)^2=\frac{9}{2}g

distance traveled in 3 rd sec=\frac{9}{2}g-2g=\frac{5}{2}g

so we can see that distance traveled in each successive second is increasing

5 0
3 years ago
A rock dropped on the moon will increase it's speed from 0 m/s to 8.15 m/s in about 5 seconds what is the acceleration of the ro
Lunna [17]

Using the formula:


a = (Vf - Vi) / t


Our initial velocity is 0 m/s, and our final velocity is 8.15 m/s, with a time period of 5 seconds:


a = (8.15 - 0.0) / 5

a = 1.63 m/s^2


If you know the acceleration due to gravity on the Moon, you can confirm this answer. The recorded gravitational acceleration on the Moon is 1.62 m/s^2.

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Which of these is an advantage of using models to study tectonic plate movements?
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Actual plate movements can be made les frequent.
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