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levacccp [35]
3 years ago
15

A heat engine: A) converts heat input to an equivalent amount of workB) converts work to an equivalent amount of heat C) takes h

eat in, does work, and loses energy heat D) uses positive work done on the system to transfer heat from a low temperature reservoir to a high temperature reservoir E) uses positive work done on the system to transfer heat from a high temperature reservoir to a low temperature reservoir
Physics
1 answer:
Masja [62]3 years ago
3 0

Answer:

C. Takes heat in, does work, and loses energy heat.

Explanation:

Heat engine is a system makes use of thermal energy (heat) to in order to do mechanical work.

This occurs by converting the heat into mechanical energy. This energy is then used to do work.

The key characteristic of a heat engine is that the substance with which work is done by, goes from a higher temperature to a lower temperature.

Hence, it loses heat as it does work.

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A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. suppose that a storm is in progress wit
Agata [3.3K]

Before we answer this question, let us first understand what alternate hypothesis is.

The alternative hypothesis is the hypothesis which is used in the hypothesis testing and this is opposite to the null hypothesis. This is the test hypothesis which is usually taken to be that the observations are the result of a real effect in an experiment.

In this case since what we want to set up is the statistical test to see if the waves are dying down, then this means we are trying to determine if the wave height are decreasing, so lesser than 16.4 feet. Therefore:

The alternative hypothesis would state                 (ANSWER)

Ha: μ less than 16.4 feet and P-value area is on the left of the mean.

 

While the null hypothesis is the opposite and would state

H0: mu equals 16.4 feet 

4 0
3 years ago
Use the drop-down menu to complete the statement.
SOVA2 [1]

Answer:

static discharge

Explanation:

I hope this helps

7 0
3 years ago
Read 2 more answers
What type of cell is the only kind that has centrioles?
Dmitrij [34]
Centrioles are found in eukaryotic cells!
6 0
3 years ago
Determine experimentally which rotational axis yields the maximum rotational inertia (i.e., moment of inertia) and which yields
Law Incorporation [45]

Answer:

  the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

Explanation:

For this exercise we use the definition moment of inertia

          I = ∫ r² dm

for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are

at one end

           I₁ = ⅓ mL²

in in center

           I₂ = \frac{1}{12} m L²

There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder

           I₃ = \frac{1}{2} m r²

remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small

when examining the different moments of inertia:

     the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

3 0
2 years ago
A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R=13\Omega

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper  wire=Sum of resistance of two piece of wires

r+7r=13

8r=13

r=\frac{13}{8}ohm

Resistance of long piece of wire=7\times\frac{13}{8}=\frac{91}{8}\Omega

Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

Length of long piece of  wire=L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L

% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

8 0
3 years ago
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