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Shtirlitz [24]
3 years ago
7

Why is the air drag on a baseball different than it would be for a smooth ball with no stitches? How does this apply to the desi

gn of a golf ball?
Physics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

The stitches and dimples around a baseball  and a golf ball respectively, disturbs the air drag on the balls once they are in motion, allowing the them to travel more easily.

Explanation:

The stitches on a baseball disturbs the air drag on the ball when the ball is in motion, allowing the ball to travel more easily. Depending on the orientation of the ball in flight, the drag changes as the flow is disturbed by the stitches.  

A smooth ball with no stitches or dimples has more air drag that opposes the motion.

A golf ball is smooth ball with dimples to create a thin turbulent boundary layer of air that clings to the ball's surface. This allows the smoothly flowing air to follow the ball's surface a little farther around the back side of the ball, thereby decreasing the size of the wake, and allowing the ball to travel more easily.

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1) A boy drags a wooden crate with a mass of 20 kg, a distance of 12 m, across a rough level floor at a constant speed of 1.5 m/
mojhsa [17]

Answer: a) 49.560 and 21.13 b) i) 50 N, ii) 196 N iii) 196 N iv) 47.685 N

c) i) 594.72 ii) 0 iii) 0 iv) 0

d) 594.72

Explanation: question a)

The force is inclined at an angle of 25° to the horizontal

The horizontal component of force = 50 cos 25° = 49.560 N

The vertical component of force = 50 sin 30°= 21.130N

Question b)

i) according to the question applied force is 50 N

ii) if g = 9.8m/s², w=mg where m = mass of object = 20kg hence weight = 20* 9.8 = 196 N

iii) the normal force is the force the floor exerts on the body as a result of the weight of the object.

Normal reaction R = W = mg, we already deduced that w = mg, hence R = 196 N.

iv) according to newton's laws of motion

F - Fr = ma

F = applied force = horizontal component of force = 49.560 N.

We need to get the acceleration (a) by using Newton laws of motion before we can be able to compute the frictional force..

The body started from rest hence initial velocity u = 0

Final velocity v = 1.5m/s distance covered (s) = 12m

v ² = u² + 2as

But u = 0

v² = 2as

1.5² = 2(a) * 12

2.25 = 24a

a = 2.25/24 = 0.09735m/s²

From F - Fr = ma

49.560 - Fr = 20 * 0.09735

49.560 - Fr = 1.875

Fr = 49.560 - 1.875

Fr = 47.685 N

Question c)

i) The applied force = 49.560 N, distance covered = 12m

Work done = force * distance

Work done = 49.560 * 12

Work done = 594.72 J

ii) the weight of the object does not make the object move a distance, hence work done = 0 ( since distance covered is 0)

iii) the normal force is the same thing as the weight and they did not cover any distance hence work done is zero.

iv) the frictional force does not cover any distance, hence work done is zero.

Question d)

The total work done = work done by applied force + work done by weight + work done by normal reaction + work done by frictional force.

Total work done = 594.72 + 0 + 0 + 0 = 594.72 J

8 0
3 years ago
Relativistic velocity is of the order of _____ of velocity of light A- 1/15th of the velocity of light B-1/20th of the velocity
ratelena [41]

Answer:

Relativistic velocity is of the order of 1/10th of the velocity of light

Explanation:

We define relativistic speed (or velocity) as a speed that is a significant fraction of the speed of light: c = 3*10^8 m/s

Such that for these speeds, the special relativity theory starts to apply (the relativity effects starts to apply).

Usually, we define relativistic speeds as those that are of the order (or larger) of c/10, which is one-tenth of the speed of light.

Then the correct option is C:

Relativistic velocity is of the order of 1/10th of the velocity of light

4 0
3 years ago
What is the acceleration of the the object during the first 4 seconds?
AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

6 0
3 years ago
Would someone plz help a shister outttt
tiny-mole [99]

Yaaaas, do you watch James Charles!?

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=help%20%5C%3A%20mo%20%5C%3A%20ako%20%5C%3A%20please.." id="TexFormula1" title="help \: mo \: a
morpeh [17]

bentar mo numpang cerita nih

jadi gini

eist yg takut cerita horor Jan di baca

awokawokawok

ok lanjut ya dek ke cerita nya :)

jadi gini di jalan,jalan lalu lintas di kampung,,,,em kyk gini,,,hmm...... kyk mana ku ceritakan ya dek,,,,bingung aku soalnya,,,,,hmm....kyk gini lah,,,,,,,,jalan ini di tengah² kebun/ladang nah kan,,,,, sebenarnya ada dua jalan mo pergi keluar masuk dari kampung ku ke kampung tetanga jadi pejalan kaki lebih suka lewat jalan tikus,,,,,yg punya mobil,kereta/motor,sepeda lewat jalan yg horornl itu yg kubilng tadi itu......,,,,nah,,,,,aku sama kawan²ku lewat jalan yg horor ini,,,,,,nah ngk nyangka ku lihat sosok putih,,,,y aku masih berpikir itu ngk bener ,,,,,trussss dua hari kemudian aku mo pergi ke kampung tetanga pake sepeda,,,,aneh ny sepeda aku berat dan,,,da-dan aku lihat sosok putih itu lagi ,,,aku jadi ngebut deh ,,,,Untung aja aku ngk jatuh ,,,,,klw di bilang suruk² ,,,setiap jalan aku ntah sama siapa² ttp ku lihat sosok putih itu,,,,nah ketika sore² aku jalan sama temen ku,,,,,eh ku lihat lagi,,,,aku penasaran aku aja deh temen ku buat nengok,,,sosok putih itu,,,,ngk nyangka sosok putih itu udh ngk ada ,,,,aneh ngab :v

dah lah sampe disini aja dulu ya dek

byee byee

............. ... .

6 0
2 years ago
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