Why is the air drag on a baseball different than it would be for a smooth ball with no stitches? How does this apply to the desi
1 answer:
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As we know that here gun + bullet system is isolated from all other external force system
so here the momentum of system is always conserved
so we will say
here we know that
now we will have
by solving above equation we will have
Here in first case both balls will exert electrostatic force on each other
due to this electrostatic force the two balls will repel each other
Apart from this there will be gravitational force on the two balls which is vertically downwards
Now here we know that as the electrostatic force of repulsion will increase between two balls then the angle between the two balls will be more as the horizontal force will separate the two balls
Part b)
As we decrease the charge on one ball then the net electrostatic force between two balls will decrease as we know that this force will depends on the product of two charges
so here the angle between the two balls will decrease and the two balls will come closer.
Also by the free body diagram of two balls we can see that all the forces on the balls are same so the angle made by the ball with the vertical is same for both the balls
so here the angle that ball l makes with the vertical will be equal to the angle that ball 2 makes with the vertical.
