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2 years ago

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A student wants to prepare a 1.0-liter solution of a specific molarity. The student determines that the mass of the solute needs

to be 30. Grams. What is the proper procedure to follow?

1 answer:

aliina [53]2 years ago

7 0

Answer:

The answer to your question is given below

Explanation:

The procedure to prepare a 1.0-liter solution of a specific molarity is as follow:

Step 1:

Determine mass of the solute needed. In this case it is 30g as given from the question.

Step 2:

Weigh the 30g from the sample of the solute using a weighing balance.

Step 3:

Put the 30g of the solute in a 500mL beaker, add adequate water and stir until it dissolves completely.

Step 4:

Transfer this solution from the 500mL to a 1L volumetric flask and make it up to the mark.

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At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107

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Answer:

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

Explanation:

The bulk modulus is represented by the following differential equation:

$K = - V\cdot \frac{dP}{dV}$

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$K$ - Bulk module, measured in pascals.

$V$ - Sample volume, measured in cubic meters.

$P$ - Local pressure, measured in pascals.

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The final volume is predicted by:

$V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }$

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$V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }$

$V_{f} \approx 0.996\,m^{3}$

Change in volume due to increasure on pressure is:

$\Delta V = V_{o} - V_{f}$

$\Delta V = 1\,m^{3} - 0.996\,m^{3}$

$\Delta V = 0.004\,m^{3}$

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