A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is
1 answer:
To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,
Frequency
Speed of sound in air
The definition of wavelength is,
Here,
v = Velocity
f = Frequency
Replacing,
Therefore the wavelength of that tone in air at standard conditions is 0.589m
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Answer:
The options are approximations of the exact answers:
A)
B)
C)
D) Toward the inner wall
E)
Explanation:
A) The electric field in a parallel plate capacitor is given by the formula , where
and in our case
and, for air,
, so we have:
B) The K+ ion has one elemental charge excess, so its charge is , and the force a charge experiments under an electric field E is given by F=qE, so we have:
C) The potential difference between two points separated a distance d under an uniform electric potential E is given by , so we have:
D) The electic field goes from positive to negative charges, so it goes towards the inner wall.
E) The work done by an electric field through a potential difference on a charge Q is
, and is equal to the kinetic energy imparted on it, so we have: