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3 years ago

9

A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is

the wavelength of that tone in air at standard conditions?

1 answer:

tester [92]3 years ago

3 0

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency $= f = 562Hz$

Speed of sound in air $= v = 331m/s$

The definition of wavelength is,

$\lambda = \frac{v}{f}$

Here,

v = Velocity

f = Frequency

Replacing,

$\lambda = \frac{331m/s}{562Hz}$

$\lambda = 0.589m$

Therefore the wavelength of that tone in air at standard conditions is 0.589m

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A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w

salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

$Ff = m*a$

$\mu*N = m*a$

$\mu*m*g = m*a$

$a=\mu*g=2.9m/s^2$

With a sum of torque on the ball:

$Ff*R = I*\alpha$

$\mu*m*g*R = 2/5*m*R^2*\alpha$

$\alpha=5/2*\mu*g/R=65.9rad/s^2$

Replacing both accelerations:

$Vo - a*t=\alpha*t*R$

$7.5 - 2.9*t=65.9*t*0.11$

t=0.74s

The distance will be:

$D = Vo*t-1/2*a*t^2$

$D = 4.76m$

Final velocity:

$Vf=Vo-a*t$

Vf=5.35m/s

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3 years ago

What happen when a star dies?

Vera_Pavlovna [14]

It depends on the size of the star. If it's size was normal then it cools down into White dwarf, then a black dwarf. If a really huge star dies, then we can see a "Supernova" from that.

Hope this helps!!

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3 years ago

If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot

Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=I_{1}+I_{2}$

$I=(m+m_{1})\times r^2+(m+m_{2})\times r^2$

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

$I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2$

$I=117.45\ kg-m^2$

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

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3 years ago

Which combination of temperature and pressure correctly describes standard temperature and pressure

raketka [301]

Answer: A combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.

Explanation:

The term standard temperature and pressure is also known as STP and it is most commonly used when we want to calculate the density of a gas.

The term standard temperature means $32^{o}$ Fahrenheit or $0^{o}C$ or 273 Kelvin. On the other hand, term standard pressure means 1 atmosheric pressure of a gas.

Thus, we can conclude that a combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.

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3 years ago

A 2kg bowling ball rolls at a speed of 5 m/s on a roof of the building that is 40 meters tall. What is the kinetic energy

MrRa [10]

The kinetic energy is $\frac 1 2 m v^2$ and the height of the building doesn't matter at all.

$E = \frac 1 2 m v^2 = \frac 1 2 (2)(5)^2 = 25$ joules

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2 years ago