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3 years ago

What's ur father put is ur name

Physics

2 answers:

djverab [1.8K]3 years ago

6 0

Nothing he left lol pain

Aleksandr [31]3 years ago

3 0

Answer:

Explanation:

God

ily and my father does too lol

Merry Christmas

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Date:

tia_tia [17]

Answer:

don't know I just want point for answers

4 0

3 years ago

An olympic high diver has gravitational potential energy because of her height. as she dives, what becomes of her energy just be

sammy [17]

An Olympic high diver has gravitational potential energy because of her height. As she dives, kinetic energy becomes of her energy just before she hits the water.

Gravitational potential energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field. In simple terms, it can be said that gravitational potential energy is an energy that is related to gravitational force or to gravity.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

When the high diver is standing stable and not moving , that diver has a gravitational potential energy because of the height . The moment she dives , before hitting the water , from being stationary she gained some momentum and come in motion , due to motion her gravitational potential energy will change to kinetic energy before hitting the ground.

To learn more about Gravitational potential energy here

brainly.com/question/15978356

#SPJ4

6 0

1 year ago

Find the acceleration if a 32.5 N force is<br> used on an object that has a mass of<br> 128.6 kg.

Sholpan [36]

Answer:

Acceleration=3.95

Explanation:Use the formula a=m/f

a=128.6/32.5

a=3.95

3 0

3 years ago

A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h

Veronika [31]

Answer:

(A) Speed will be $44.18\times 10^4m/sec$

(b) Change in kinetic energy = $1560\times 10^{-19}$

Explanation:

We have given mass of proton $m=1.67\times 10^{-27}kg$

Acceleration of the proton $a=2.50\times 10^{12}m/sec^2$

Initial velocity u = $1.60\times 10^4$ m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

$v^2=u^2+2as$

$v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039$

$v=44.18\times 10^4m/sec$

(b) Initial kinetic energy $KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2$

Final kinetic energy $KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2$

So change in kinetic energy $\Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J$

6 0

3 years ago

A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?

Lyrx [107]

100N describes the weight of the sandbag, while 100kg is the mass of the sandbag.

To calculate acceleration, divide your weight by the mass, thus the accleration is:

$100N/100kg = 1(m/s^2)$

7 0

3 years ago

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What's ur father put is ur name​

What's ur father put is ur name