Answer:
Depends
Explanation:
This depends on the amount of work the energy requires
1) We use:
2as = v² - u², with v = 0,
to find the acceleration of the arrow.
2 x 0.038 x a = -(25)²
a = -8.22 x 10³ m/s²
F = ma
F = 6.5 x 10⁻² x -8.22 x 10³
F = -534.2 N; the negative direction indicates that the force is in the opposite direction of the motion.
B) The arrows force is the same but in the opposite directioin.
534.2 N
C) a = -8.22 x 10³ m/s²
s = -(65)²/(2 x -8.22 x 10³)
s = 25.7 cm
Answer:
79.2 m/s
Explanation:
θ = angle at which projectile is launched = 29.7 deg
a = initial speed of launch = 130 m/s
Consider the motion along the vertical direction
v₀ = initial velocity along the vertical direction = a Sinθ = 130 Sin29.7 = 64.4 m/s
y = vertical displacement = - 108 m
a = acceleration = - 9.8 m/s²
v = final speed as it strikes the ground
Using the kinematics equation
v² = v₀² + 2 a y
v² = 64.4² + 2 (-9.8) (-108)
v = 79.2 m/s
Answer:
P-value of the test statistic is 2.499
Explanation:
given data:
size sample is 24
sample mean is 414 gm
standard deviation is 15
Null hypotheis is
level of significance is 0.01
from test statics
degree od freedom is = n -1
df = 24 -1 = 13
t = -1.959
from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499
820 meters is the longest
