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katrin [286]
3 years ago
9

Evaluate 4m(3m-2) when m=-3.3

Mathematics
1 answer:
Bad White [126]3 years ago
3 0
F(m)=4m(3m-2)
f(m)=12(m^2)-8m
f(-3.3)=12(-3.3^2)-8(-3.3)
f(-3.3)=12(10.89)-(-26.4)
f(-3.3)=130.68+26.4
f(-3.3)=157.08
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Answer:

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Step-by-step explanation:

Given that:

((a, b), (c, d))\in R

Where R is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

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Here we need to prove:

\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R

As per the given relation:

((a,b), (a,b) ) \Rightarrow ab =ab which is true.

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2. Now, let us check symmetric property:

Symmetric property means:

\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R

Here we need to prove:

\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R

As per the given relation:

((a,b),(c,d)) \in R means ad = bc

((c,d),(a,b)) \in R means cb = da\ or\ ad =bc

Hence true.

\therefore R is symmetric.

3. R to be transitive, we need to prove:

if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R

((a,b),(c,d)) \in R means ad = cb.... (1)

((c,d), (e,f)) \in R means fc = ed ...... (2)

To prove:

To be ((a,b), (e,f)) \in R we need to prove: fa = be

Multiply (1) with (2):

adcf = bcde\\\Rightarrow fa = be

So, R is transitive as well.

Hence proved that R is an equivalence relation.

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