2 years ago

What are two characteristics of transverse waves that are not found in longitudinal waves

Physics

1 answer:

BigorU [14]2 years ago

4 0

Answer:

I don't know I'm sorry I will tell you another answer asks me to

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You're trying to stop a car that is rolling down-hill. Gravity is pulling it forward with a force of 200 N. If the car has a mas

lara31 [8.8K]

Answer:

no idea .

Explanation:

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3 years ago

In an electric header 500w is written. What is its meaning

Fiesta28 [93]

Answer:

Because it's wattage is 500W.

Explanation:

This is its mearurement

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2 years ago

A coil of wire consists of 20 turns, each of which has an area of 0.0015 m2. A magnetic field is perpendicular to the surface wi

stepan [7]

Answer:

magnitude of the induced emf in the coil is 0.0153 V

Explanation:

Given data

no of turns = 20

area = 0.0015 m²

magnitude B1 = 4.91 T/s

magnitude B2 = 5.42 T/s

to find out

the magnitude of the induced emf in the coil

solution

we know here

emf = -n A d∅ /dt

so here n = 20 and

A = 0.0015

and d∅ = B2 - B1 = 5.42 - 4.91

d∅ = 0.51 T and dt at 1 sec

so put all value

emf = -n A d∅ /dt

emf = -20 (0.0015) 0.51 / 1

emf = - 0.0153

so magnitude of the induced emf in the coil is 0.0153 V

7 0

2 years ago

SELECT ALL THAT APPLY!! Which of the following are considered SIGNS that a chemical reaction occurred?

MAXImum [283]

Answer:

Formation of a Precipitate

Unexpected Color Change

Formation of a Gas

Explanation:

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2 years ago

Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec

Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

$\displaystyle \omega=\frac{v}{r}$

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

$\omega=2\pi f$

Where:

f = frequency

Solving for f:

$\displaystyle f=\frac{\omega}{2\pi}$

Since the frequency is calculated when the number of revolutions n and the time t are known:

$\displaystyle f=\frac{n}{t}$

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

$\displaystyle \omega=\frac{25}{90}$

$\displaystyle \omega=0.278\ rad/s$

Now we calculate f:

$\displaystyle f=\frac{0.278}{2\pi}$

$f=0.04421\ Hz$

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0

2 years ago