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3 years ago

7

What are two characteristics of transverse waves that are not found in longitudinal waves

1 answer:

BigorU [14]3 years ago

4 0

Answer:

I don't know I'm sorry I will tell you another answer asks me to

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The origin of the universe remains a question. The most accepted theory, that suggests our universe started as a hot, dense, com

svlad2 [7]

<span>C option is correct which is big bang theory. According to this theory in start there was no system of earth and all planets were combined. Then there was explosion due to which planets originated and the system of earth and universe started.</span>

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3 years ago

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The energy band gap of GaAs is 1.4 eV. Calculate the optimum wavelength of light for

notsponge [240]

Answer:

The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm

Explanation:

The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy

Energy of light waves is given as

E = hf

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = Frequency of the light

The frequency is then further given as

f = (c/λ)

c = speed of light = (3.0 × 10⁸) m/s

λ = wavelength of the light = ?

E = (hc/λ)

λ = (hc/E)

Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J

λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)

λ = (8.863 × 10⁻⁷) m = 886 nm

Hope this Helps!!!

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3 years ago

He diagram shows a person holding a bow and arrow.

olganol [36]

Answer:

B Relesing the string

Explanation:

got it right on edge

5 0

3 years ago

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Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ an

Alex

Answer:

0.33 Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33 Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: $\frac{V^2}{R}$ which gives:

4^2 / 2 = 8 Watts

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3 years ago

A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.

Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

k x = m g

$k = \dfrac{mg}{x}$

$k = \dfrac{6.4 \times 9.8}{0.28}$

k = 224 N/m

b) $f = \dfrac{\omega}{2\pi}$

$\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}$

$f =0.94\ Hz$

c) $v_b = -v cos \omega t$

$v_b = -5.1 \times cos (5.92 \times 0.42)$

$v_b = 4.04\ m/s$

d) $a_{max} = v \omega$

$a_{max} = 4.04 \times 5.92$

$a_{max} =23.94\ m/s^2$

e) $Y =- A sin (\omega t)$

$A = \dfrac{v}{\omega}$

$A = \dfrac{4.04}{5.92}$

A = 0.682 m

$Y =- 0.682 \times sin (5.92 \times 0.42)$

$Y =- 0.42$

Force = $m \omega^2 |Y|$

= $6.4 \times 5.92^2\times 0.42$

F = 94.20 N

4 0

3 years ago