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babunello [35]
3 years ago
11

A space vehicle is traveling at 5425 km/h relative to the Earth when the exhausted rocket motor (mass 4m) is disengaged and sent

backward with a speed of 81 km/h relative to the command module (mass m). What is the speed of the command module relative to Earth just after the separation
Physics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

V_{cE}=1489m/s

Explanation:

Given data

Space vehicle speed=5425 km/h relative to earth

The rocket motor speed=81 km/h  and mass 4m

The command has mass m

From the conservation of momentum as the system isolated

p_{i}=p_{f}\\

Since the motion in on direction we can drop the unit vector direction

MV_{i}=4mV_{mE}+mV_{CE}

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.

The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

V_{mE}=V_{mc}+V_{cE}

Where Vmc is the velocity of motor relative to command

This yields

5mV_{i}=4m(V_{mc}+V_{cE})+mV_{cE}\\5V_{i}=4V_{mc}+5V_{cE}

Substitute the given values

V_{cE}=\frac{5V_{i}-4V_{mc}}{5}\\ V_{cE}=5425*\frac{1000}{60*60}(m/s)-\frac{4}{5}*81\frac{1000}{60*60}(m/s)\\  V_{cE}=1489m/s

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Naily [24]

Answer:

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5 0
2 years ago
Normal body temperature. the average normal body temperature measured in the mouth is 310 k . what would celsius and fahrenheit
faltersainse [42]
The question is simply asking us to convert one unit, in this case temperature, to another unit. To do this, we need conversion factors to multiply, divide or relate to the original measurement. We do as follows:

Celsius = Kelvin - 273.15
310 - 273.15 = 36.85 degrees celsius

Fahrenheit = <span> (°</span>C<span> × </span>9<span>/5) + 32
</span> (36.85<span> × </span>9<span>/5) + 32 = 98.33 degrees fahrenheit
</span>
Hope this helps.

7 0
3 years ago
What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?
Nuetrik [128]

Answer:

9.8 m/s/s

Explanation:

The numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall is 9.8 m/s/s. This is called the acceleration due to gravity.

8 0
3 years ago
Read 2 more answers
A far-sighted person has a near-point of 80 cm. To correct their vision so that they can see objects that are as close as 10 cm
bekas [8.4K]

Answer:

f = 8.89 cm

Explanation:

As we know that Far sighted person has near point shifted to 80 cm distance

so he is able to see the object 80 cm

now the distance of lens from eye is 2 cm

and the person want to see the objects at distance 10 cm

so here the image distance from lens is 80 cm and the object distance from lens is 8 cm

now from lens formula we have

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

-\frac{1}{80} + \frac{1}{8} = \frac{1}{f}

f = 8.89 cm

3 0
3 years ago
A baseball travels at a velocity of 45.3 m/s towards second base for 17 s. Calculate the displacement of the ball.
Sergeu [11.5K]

Answer:

770.1 m

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 45.3 m/s

Time (t) = 17 s

Displacement (d) =?

Velocity is defined according to the following formula:

Velocity = Displacement /Time

With the above formula, we can obtain the displacement of the ball as follow:

Velocity = Displacement /Time

45.3 = Displacement / 17

Cross multiply

Displacement = 45.3 × 17

Displacement = 770.1 m

Therefore the displacement of the ball is 770.1 m

8 0
2 years ago
Read 2 more answers
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