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gtnhenbr [62]
2 years ago
10

A=100m/s2 Vi=10m/s T=10sec Vf?

Physics
1 answer:
IrinaK [193]2 years ago
3 0

Answer:

v=u+at

v= 10+100×10

v = 10+1000

v = 1010 m/s

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A device that uses electricity and magnetism to create motion is called a _________motor,magnet,generator . In a reverse process
lawyer [7]
A device that uses electricity and magnetism to create motion is called a "Motor" (which converts electric energy into mechanical energy) & <span>In a reverse process, a device that uses motion and magnetism can be used to create "Electromagnetism".

In short, 1st Blank = Motor
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5 0
3 years ago
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A ball rolls off a table with a horizontal velocity of 3 m/s. If it takes 0.3 seconds for the ball to reach the floor, how high
LekaFEV [45]

The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Horizontal velocity (u) = 3 m/s
  • Time (t) = 0.3 s
  • Acceleration due to gravity (g) = 10 m/s²
  • Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

Learn more about motion under gravity:

brainly.com/question/26275209

6 0
2 years ago
Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
mamaluj [8]

Answer: 9000 kgm/s

Explanation:

Mass of car = 1500 kg

Speed by which car moves = 6 m/s. Momentum of the car = ?

Recall that:

Linear momentum = Mass x Speed

= 1500kg x 6m/s

= 9000 kgm/s

Thus, the linear momentum of the car is 9000 kgm/s

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3 years ago
The force of gravity is an inverse square law. this means that, if you double the distance between two large masses, the gravita
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F~1/r²
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3 years ago
Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

v_f^2=v_i^2+2ax

Where,

v_f = Final velocity

v_i = Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

F_f = \mu_k (mg)  \rightarrowFrictional Force

F = ma \rightarrow Force by Newton's second Law

Where,

m = mass

a= acceleration

\mu_k = Kinetic frictional coefficient

g = Gravity

Equating both equation we have that

F_f = F

\mu_k mg=ma

a = \mu_k g

Therefore,

v_f^2=v_i^2+2ax

0=v_i^2+2(\mu_k g)x

Re-arrange to find x,

x = \frac{v_i^2}{2(-\mu_k g)}

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

3 0
2 years ago
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