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gtnhenbr [62]
2 years ago
10

A=100m/s2 Vi=10m/s T=10sec Vf?

Physics
1 answer:
IrinaK [193]2 years ago
3 0

Answer:

v=u+at

v= 10+100×10

v = 10+1000

v = 1010 m/s

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2 years ago
A 0.75 kilogram apple is thrown upward from the ground. The apple reaches a height of 5.5m, what is the beginning gravitational
MaRussiya [10]

Answer:

U(0.0m) = 0J

U(5.5m) = 40.42 J

Explanation:

The gravitational potential energy is given by the following formula:

U=mgh

h: height

m: mass of the apple = 0.75kg

g: gravitational acceleration = 9.8m/s^2

When the apple is at 5.5m from the ground the gravitational potential energy is:

U=(0.75kg)(9.8m/s^2)(5.5m)=40.42\ J

when the apple is on the ground you have:

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Which of the following is not in the form of waves?
Nady [450]
C. Seismic energy
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Read 2 more answers
A person weighing 0.9 kN rides in an elevator that has a downward acceleration of 1.9 m/s^2. The acceleration of gravity is 9.8
Keith_Richards [23]

Answer:

The magnitude of the force is 0.7255kN

Explanation:

The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:

(force of floor F) = (mass of person m) x [ (grav. acceleration g) - (elevator acceleration a) ]

in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:

F = m\cdot(g-a)

We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:

900 N = m\cdot g \implies m = \frac{900N}{9.8 \frac{m}{s^2}}

So

F = \frac{900N}{9.8 \frac{m}{s^2}}\cdot(9.8-1.9)\frac{m}{s^2}\approx 725.5N=0.7255kN

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2 years ago
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