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wolverine [178]

3 years ago

14

The density of a certain type of plastic is 0.81 g/cm3. If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick, w

hat is its mass?
mass = _____ x 10_____g

g
Enter your answer in scientific notation.

1 answer:

crimeas [40]3 years ago

8 0

<u>Answer:</u> The mass of plastic sheet is $8.1\times 10^4g$

<u>Explanation:</u>

The plastic sheet is in the form of cuboid. To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.0 m = 1000 cm (Conversion factor: 1 m = 100 cm)

b = breadth of cuboid = 1.0 m = 100 cm

h = height of cuboid = 1 cm

Putting values in above equation, we get:

$V=1000\times 100\times 1=10^5cm^3$

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of plastic sheet = $0.81g/cm^3$

Volume of plastic sheet = $10^5cm^3$

Putting values in equation 1, we get:

$0.81g/cm^3=\frac{\text{Mass of plastic sheet}}{10^5cm^3}\\\\\text{Mass of plastic sheet}=8.1\times 10^4g$

Hence, the mass of plastic sheet is $8.1\times 10^4g$

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Answer:

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3 years ago

a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp

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Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

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where,

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We are given:

$n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL$

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b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

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3 years ago

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<h3>Further explanation</h3>

Given

Reaction

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701,52 g of KMnO4

Required

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Solution

mol KMnO4 (MW=158,034 g/mol) :

mol = mass : MW

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Hello,

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