Answer:
Weight % of NH₃ in the aqueous waste = 2.001 %
Explanation:
The chemical equation for the reaction

Moles of HCl = Molarity × Volume
= 0.1039 × 31.89 mL × 
= 0.0033 mole
Total mass of original sample = 25.888 g + 73.464 g
= 99.352 g
Total HCl taken for assay = 
= 0.1083 g
Moles of NH₃ = 
= 0.03047 moles
Mass of NH₃ = number of moles × molar mass
Mass of NH₃ = 0.03047 moles × 17 g
Mass of NH₃ = 0.51799
Weight % of NH₃ =
%
Weight % of NH₃ in the aqueous waste = 2.001 %
Glucose is converted into pyruvate in a process called Glycolysis which aim in production of energy for most of tissues inside our body... then pyruvate is converted into acetyl coA with the help of pyruvate dehydrogenase enzyme then this acetyl coA enters citric acid cycle for production of more energy
One Acetyl molecule will be produced form one pyruvic acid. and two pyruvic acid molecule will be formed from one glucose molecule during glycolysis. so from
2 acetyl molecules → one glucose molecules.
For 24 acetyl molecules → ??
24*1/2 = 12.
The answer is 12 Glucose molecules.
30.58 grans of Calcium ...
The formula equation is Ca + F2 = CaF2.
Hope it helps.