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4 years ago

HELP! 40 POINTS

Chemistry

1 answer:

xxTIMURxx [149]4 years ago

8 0

Answer:

idk neeed help to

Explanation:

man

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A rock displaces 1,500 mL of water. The volume of the rock is

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When Xavier places his hands near a light bulb, he notices that certain areas around the light bulb are warmer than others.

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Consider a new temperature scale (ºa) based on the melting and boiling points of ammonia (nh3) which are taken as 0.0 ºa and 100

Nady [450]

Answer:- 25.0 degree C corresponds to 231 $^0A$ .

Solution:- Let's say the two temperature scales have linear relationship. The equation of line is:

$y=mx+c$

where, m is the slope of the line and c is the intercept. Let's take the new temperature scale, $^0A$ for y and $^0C$ as $x$ . The equation would be looking as:

$^0A=m*^0C+c$

melting point of ammonia in new scale is 0.0 $^0A$ and in celsius scale it is -77.7 degree C. Boiling point in new scale is 100.0 $^0A$ and in celsius scale it is -33.3 degree C.

Let's plug in the values in the equation of line for melting points and boiling points to make two equations that we would solve:

For melting point:- $0.0=m(-77.7)+c$

For boiling point:- $100=m(-33.3)+c$

Now, we solve these two equations to find out the slope of the equation that is the value of m. Let's multiply the second equation by negative means changing all the signs from negative to positive and vice versa.

$0.0=m(-77.7)+c$

$-100=m(+33.3)-c$