A=1/2 b*h
So substitute it in 1/2*1/2*4
1/2*1/2= 1/4
1/4*4= 4/4= 1 so the entrance is 1 foot tall
Answer:
Step-by-step explanation:
y = 3x - 5
6x + 3y = 15
Substitute the first equation into the second
6x + 3(3x - 5) = 15
6x + 9x - 15 = 15
15x = 30
x = 2
Then use the answer in the first equation and solve
y = 3(2) - 5
y = 6 - 5
y = 1
Answer:
B
Step-by-step explanation:
Count how many times a 1, 2, or 3 appears. Of the digits, 7 are 1s, 2s, or 3s.
Answer:
Part a) Is a growth function
Part b) The function's percent rate of change is 160%
Step-by-step explanation:
we have
![f(x)=0.3(2.6^x)](https://tex.z-dn.net/?f=f%28x%29%3D0.3%282.6%5Ex%29)
This is a exponential function of the form
![f(x)=a(b^x)](https://tex.z-dn.net/?f=f%28x%29%3Da%28b%5Ex%29)
where
a is the initial value or y-intercept
b is the base of the exponential function
If b> 1---> we have a growth function
if b< 1---> is a decay function
r is the percent rate of change
b=(1+r)
In this problem we have
![a=0.3](https://tex.z-dn.net/?f=a%3D0.3)
![b=2.6](https://tex.z-dn.net/?f=b%3D2.6)
The value of b >1
so
Is a growth function
Find the value of r
![r=b-1=2.6-1=1.6](https://tex.z-dn.net/?f=r%3Db-1%3D2.6-1%3D1.6)
convert to percentage
![r=1.6*100=160\%](https://tex.z-dn.net/?f=r%3D1.6%2A100%3D160%5C%25)
The average speed of the whole journey of car based mentioned speeds is 48 km/hr.
The average speed is calculated by the formula -
average speed = total distance covered ÷ total time taken. The total distance covered is sum of distance of first and return journey. Total distance covered = 100 + 100
Performing addition
Total distance covered = 200 kilometres
Now total time taken = time taken on first journey + time taken for return journey
Total time taken = distance/speed + distance/return speed
Total time taken = 100/60 + 100/40
Performing division
Total time taken = 5/3 + 5/2
Total time taken = 10 + 15/6
Total time taken = 25/6 hour
Average speed = 200/(25/6)
Average speed = (200×6)/25
Performing division and multiplication
Average speed = 48 km/hr
Learn more about speed -
brainly.com/question/13943409
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