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Ahat [919]
4 years ago
12

Which object(s) formed last in our solar system?

Physics
1 answer:
alexira [117]4 years ago
5 0

Answer:

first option bro

Explanation:

by the way if you play free fire give me your uid on the comment section

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Which answer is it??
IrinaK [193]

Answer:

hmm...

Explanation:

8 0
3 years ago
Read 2 more answers
A 26.4 g silver ring (cp = 234 J/kg·°C) is heated to a temperature of 66.2°C and then placed in a calorimeter containing 4.94 ✕
Slav-nsk [51]

Answer:

The final temperature of the mixture = 64.834 °C.

Explanation:

Heat lost by the silver ring = heat gained by the water + heat transferred to the surrounding.

c₁m₁(t₁-t₃) = c₂m₂(t₃-t₂) + Q..............Equation 1

Where c₁ = specific heat capacity of the silver copper, m₁ = mass of the silver copper, t₁ = initial temperature of the silver copper, t₃ = final temperature of the mixture. c₂ = specific heat capacity of water, t₂ = initial temperature of water, m₂ = mass of water, Q = energy transferred to the surrounding.

making t₃ the subject of the equation,

t₃ = [c₁m₁t₁+c₂m₂t₂-Q]/(c₁m₁+c₂m₂)........................ Equation 2

Given: c₁ = 234 J/kg.°C, m₁ = 26.4 g, t₁ = 66.2 °C, c₂ = 4200 J/K.°C, m₂ = 4.92×10⁻² kg, t₂ = 24.0 °C, Q = 0.136 J.

Substituting into equation 2

t₃ = [(234×26.4×66.2)+(4200×0.0492×24)-0.136]/[(234×26.4)+(4200×0.0492)]

t₃ = (408957.12+4959.36-0.136)/(6177.6+206.64)

t₃ = (413916.48-0.136)/6384.24

t₃ = 413916.34/6384.24

Thus the final temperature of the mixture = 64.834 °C.

6 0
3 years ago
What is the time required for sound to travel 1.75 km if the temp of the air is 20 C°?
murzikaleks [220]

Answer:

Explanation:

The 2 equations we need for this are

v=331.5+.606T and

d = rt. First we need to find the velocity using the first equation, then we will plug it into the distance equation as the rate to find the time.

v = 331.5 + .606(20.0) I used 3 sig figs for the temp instead of the 1 found in 20.

v = 331.5 + 12.1 so

v = 343.6 m/s

Now, before we can find the time in seconds, we need to convert the distance to meters.

1.75 km = 1750 m:

1750 = 343.6t so

t = 5.09 seconds

7 0
3 years ago
s it possible for a system to have negative potential energy? Is it possible for a system to have negative potential energy? No,
frez [133]

Answer: Yes it possible for a system to have negative potential energy, since the choice of the zero of potential energy is arbitrary.

Explanation:

Potential energy is defined as the energy present in an object due to its position.

Mathematically,   P.E = mgh

A potential energy can be negative also. This is because zero potential energy is arbitrary. For example, at the top of a building the choice of potential energy can be zero.

Therefore, the potential energy below the building will be negative.

8 0
4 years ago
A frictionless spring with a 4-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 30 newtons. If t
maxonik [38]

Answer:

The position for mass is x(t)=36.75sin(37.5t)

Explanation:

Let x(t) donate the position of mass at time t,Then x satisfies the differential equation

m\frac{d^2x}{dt^2} +kx=0\\here\\m=4kg\\k=30N/0.2m\\thus\\w^2=k/m=30N/0.2m*4kg=37.5

The general solution is

(x)t=C_{1}cos(37 .5t)+C_{2}sin(37.5t)

It follows

x'(t)=-37.5C_{1}sin(37.5t)+37.5C_{2}cos(37.5t)\\now\\x(0)=0\\gives\\C_{1}=0\\ and\\x'(0)=1m/s\\gives\\C_{2} =36.75

thus the position of mass is

x(t)=36.75sin(37.5t)

7 0
3 years ago
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