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bixtya [17]
3 years ago
13

Determine the mass of water in kg, if 4300 cal of energy is placed in water, resulting in a temperature change to 101.0 oC from

92.5 oC.
Chemistry
1 answer:
Airida [17]3 years ago
6 0

Answer:

0.5059kg

Explanation:

The heat absorbed for the water is determined using the equation:7

Q = C×m×ΔT

<em>Where Q is heat absorbed (4300cal)</em>

<em>C is specific heat (1cal/g°C)</em>

<em>m is the mass in grams</em>

<em>ΔT is change in °C (101.0°C - 92.5°C = 8.5°C)</em>

<em />

Replacing:

4300cal = 1cal/g°C×m×8.5°C

505.9g = m

In kg, the mass of water is:

<h3>0.5059kg</h3>

<em />

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An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

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where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

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density=\frac{mass}{volume}

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P*V=\frac{mass}{molar mass} *R*T

Solving to get the definition of density expressed in the equation, you get:

density=\frac{mass}{V} =\frac{P*molar mass}{R*T}

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  • T= 27 C= 300 K (being 0 C=273 K)

and replacing:

density=\frac{mass}{V} =\frac{0.500 atm*44 \frac{g}{mole} }{0.082 \frac{atm*L}{mole*K} *300 K}

you get:

density= 0.89 \frac{grams}{L}

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