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3 years ago

The amount of work done to produce a sound determines which property of sound waves?

Physics

2 answers:

trapecia [35]3 years ago

5 0

The answer is D) Amplitude

Anna35 [415]3 years ago

4 0

Intensity of sound is defined by

$Intensity = \frac{Energy}{Area* time}$

So here we can say work done by us is stored in the form of energy of sound and that energy can be compared by the intensity of sound

So if we will do more work then the sound will have more energy and hence it will have more intensity

Now we know that intensity of sound is given as

$intensity = kA^2$

so more is the intensity then more work which means the amplitude will be more

So answer will be

D. amplitude

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3 years ago

A speaker at the front of a room and an identical speaker at the rear of the room are being driven at 456 Hz by the same sound s

vampirchik [111]

Answer:

2.97795 Hz

Explanation:

v = Speed of sound in air = 343 m/s

$v_r$ = Relative speed between the speakers and the student = 1.12 m/s

$f'$ = Actual frequency of sound = 456 Hz

Frequency of sound heard as the student moves away from one speaker

$f_1=f'\dfrac{v-v_r}{v}\\\Rightarrow f_1=456\dfrac{343-1.12}{343}\\\Rightarrow f_1=454.51102\ Hz$

Frequency of sound heard as the student moves closer to the other speaker

$f_2=f'\dfrac{v+v_r}{v}\\\Rightarrow f_2=456\dfrac{343+1.12}{343}\\\Rightarrow f_2=457.48897\ Hz$

The difference in the frequencies is

$f_2-f_1=457.48897-454.51102=2.97795\ Hz$

The student hears 2.97795 Hz

6 0

3 years ago

An isolated system contains a ball at rest 5 meters (m) above the ground. The ball has an initial potential energy of 250 joules

bazaltina [42]

Answer:

Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]

Explanation:

This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.

The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.

We know that the potential energy is defined by:

$E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]$

We can clear the mass from this equation:

$m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]$

When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.

In such a way that its potential energy would be transformed into kinetic energy.

$E_{k} = E_{p} \\E_{k} =kinetic energy [J]$

Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.

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3 years ago