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Soloha48 [4]
3 years ago
9

The amount of work done to produce a sound determines which property of sound waves?

Physics
2 answers:
trapecia [35]3 years ago
5 0
The answer is D) Amplitude
Anna35 [415]3 years ago
4 0

Intensity of sound is defined by

Intensity = \frac{Energy}{Area* time}

So here we can say work done by us is stored in the form of energy of sound and that energy can be compared by the intensity of sound

So if we will do more work then the sound will have more energy and hence it will have more intensity

Now we know that intensity of sound is given as

intensity = kA^2

so more is the intensity then more work which means the amplitude will be more

So answer will be

D. amplitude

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Answer:

0.5 m/sec

Explanation:

v=S÷t

 =5÷10

v=0.5 m/sec

6 0
3 years ago
In a given chemical reaction the energy of the products is less than the energy of the reactants. Which statement is true for th
Westkost [7]

Answer:

B. Energy is released in the reaction.

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What force is needed to give a 0.25-kg arrow an acceleration of 196 m/s/s
kakasveta [241]
Force (f) = ?

Acceleration (a) = 196 m/s^2

Mass (m) = 0.25 kg

F = (m) • (a)

F = (0.25) • (196)

F = 49 N

Answer : 49 N

I hope that helps you!! Any more questions??

8 0
3 years ago
Read 2 more answers
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
ki77a [65]

Answer:

The lowest possible frequency of sound for which this is possible is 1307.69 Hz

Explanation:

From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.

First, we will determine his distance from the second speaker using the Pythagorean theorem

l₂ = √(2.00²+5.00²)

l₂ = √4+25

l₂ = √29

l₂ = 5.39 m

Hence, the path difference is

ΔL = l₂ - l₁

ΔL = 5.39 m - 5.00 m

ΔL = 0.39 m

From the formula for destructive interference

ΔL = (n+1/2)λ

where n is any integer and λ is the wavelength

n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which corresponds to the smallest value of n.

Then,

0.39 = (1+ 1/2)λ

0.39 = (3/2)λ

0.39 = 1.5λ

∴ λ = 0.39/1.5

λ = 0.26 m

From

v = fλ

f = v/λ

f = 340 / 0.26

f = 1307.69 Hz

Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.

5 0
3 years ago
The space shuttle travels at a speed of about 7.6times10^3 m/s. The blink of an astronaut's eye lasts about 110 ms. How many foo
sveta [45]

Answer:

It covers distance of 9.15 football fields in the said time.

Explanation:

We know that

Distance=Speed\times Time

Thus distance covered in blinking of eye =

Distance=7.6\times 10^{3}m/s\times 110\times 10^{-3}s\\\\Distance=836 meters

Thus no of football fields=\frac{936}{91.4}=9.15Fields

7 0
3 years ago
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