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3 years ago

7

A body weighs less inside water

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

Body weighs lesser in water because of the upward force (buoyant force) which acts on our body thereby reducing our actual weight. This is our apparent weight.

Explanation:

hope it helps

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1. A block of aluminum occupies

Anvisha [2.4K]

Answer:

2700g/L

Explanation:

D=m/v

40.5g/0.015L

7 0

3 years ago

¿Quien desarrolló el método físico experimental?

Viefleur [7K]

Answer:

Explanation:

El 15 de febrero de 1564 nacía Galileo Galilei (1564-1642). Galileo Galilei es una de las figuras claves de la historia de la Ciencia, pudiéndosele considerar el primero que aplicó el método científico experimental-matemático.

7 0

3 years ago

A straight fin is made from copper (k = 388 W/m-K) and is 0.5 cm in diameter and 30 cm long. The temperature at the base of the

erastovalidia [21]

Answer:

The rate of transfer of heat is 0.119 W

Solution:

As per the question:

Diameter of the fin, D = 0.5 cm = 0.005 m

Length of the fin, l =30 cm = 0.3 m

Base temperature, $T_{b} = 75^{\circ}C$

Air temperature, $T_{infty} = 20^{\circ}$

k = 388 W/mK

h = $20\ W/m^{2}K$

Now,

Perimeter of the fin, p = $\pi D = 0.005\pi \ m$

Cross-sectional area of the fin, A = $\frac{\pi}{4}D^{2}$

A = $\frac{\pi}{4}(0.5\times 10^{-2})^{2} = 6.25\times 10^{- 6}\pi \ m^{2}$

To calculate the heat transfer rate:

$Q_{f} = \sqrt{hkpA}tanh(ml)(T_{b} - T_{infty})$

where

$m = \sqrt{\frac{hp}{kA}} = \sqrt{\frac{20\times 0.005\pi}{388\times 6.25\times 10^{- 6}\pi}} = 41.237$

Now,

$Q_{f} = \sqrt{20\times 388\times 0.005\pi\times 6.25\times 10^{- 6}\pi}tanh(41.237\times 0.3)(75 - 20) = 0.119\ W$

5 0

3 years ago

What should Ben wear to best protect himself during the experiment?

GarryVolchara [31]

Goggles, a lab coat, chemical gloves, and close- toed shoes

4 0

3 years ago

A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis

Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

..

Explanation:

The exercise is "free fall". t = $\sqrt{\frac{2h}{g} }$

Solving with this formula you find the time it takes for the stone to reach the ground (T) = 102,04 s

The heights (h) according to his time (t) are found according to the formula:

h(t) = 500 - 1/2 * g * t²

Remplacing "t" with the desired time.

4 0

3 years ago