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nikitadnepr [17]
3 years ago
5

The consecutive angles of a parallelogram measure (x+30) and 4x°. What is the measure of the smallest

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

60

Step-by-step explanation:

180=(x+30)+(4x)

Ok, combine like terms. That'll give you

180=5x+30.

Now solve for x. X is going to equal 30.

Then substitute 30 for x in the angles. One angle will be 60 and the other will be 120.

60 is smaller than 120 so that's your answer.

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Find a. Round to the nearest tenth
Drupady [299]

Answer:

a = 2.14cm to the nearest 10th =2.1

Step-by-step explanation:

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8 0
3 years ago
The simple interest on an investment of $8000 for one year is $360.
elena55 [62]
I = PRT
$360 = $8000 x R X 1
$360 = $8000 X R
$360/$8000 X R /$8000
0.045 = R
R= 0.045 * 100
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3 years ago
SNOG PLEASE HELP! (x-1)(y+8)
Leya [2.2K]

Answer:

Using FOIL we get:

xy + 8x - y - 8

4 0
3 years ago
Read 2 more answers
What is the correct evaluation of 4x2 - 2x + 5, when x is equal to 2?
meriva

Answer:

9

Step-by-step explanation:

  1. Rewrite the problem

4x2-2(2)+5

2. Solve the problem. Do the multiplication first and then the subtraction and addition

8-2(2)+5

8-4+5

4+5

9

The final answer is 9

3 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
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