Complete question:
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.
Answer:
the heat of combustion of the methanol is 402.31 kJ/mol
Explanation:
Given;
mass of water,
= 100 g
initial temperature of water, t₁ = 28 ⁰C
final temperature of water, t₂ = 58 ⁰C
specific heat capacity of water = 4.184 J/g⁰C
reacting mass of the methanol, m = 1.00 g
molecular mass of methanol = 32.04 g/mol
number of moles = 1 / 32.04
= 0.0312 mol
Apply the principle of conservation of energy;

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol
Answer:
161 mmHg
Explanation:
Ptotal= PHe +PNe
PHe= Ptotal-PNe
PHe= (600 mm Hg)-(439 mmHg)
PHe=161 mmHg
I think it’s C but I’m not sure
DENSITY = mass / volume..
g / <span>m³
g / c</span><span>m³
</span>
kg / l
The correct option is D.
The reactants that combine together to form glucose are carbon dioxide, water and energy from the sun. Six molecules of carbon dioxide combine with six molecules of water in the presence of sunlight to form glucose. The chemical equation for the reaction is given below"
6CO2 + 6H2O + Sunlight = C6H12O6.