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2 years ago

When force is applied to a breaker bar the torque can be calculated by multiplying the length of the lever by the?

1 answer:

5 0

When a force applied to a breaker bar the torque can be calculated by multiplying the<u> length of the lever</u> by the tangential component of force on the lever.

<h3>What is torque?</h3>

Torque is the <u>rotating equivalent</u> of force in physics and mechanics. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect. It illustrates how a force can cause a change in the body's rotational motion.

Torque is given by the formula :

α = r x F ( bold letters represent vector quantities)

The S.I. unit for torque is : N - m ( Newton - meter)

<h3>How do we define 1 N-m of torque?</h3>

The newton-metre is a torque unit (also known as a moment) in the SI system. The torque produced by a one newton force applied <u>perpendicularly to the end of a one metre long</u> moment arm is known as a newton-metre.

To learn more about torque:

brainly.com/question/14970645

#SPJ4

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Find the magnitude of pressure in Pascal of 150N that acts normally on area. Of 0.25m2

ycow [4]

Answer with Explanation:

When solving a problem in math, chemistry or physics, it is necessary to understand all the words and their definitions. If not, start with finding out their meanings, one by one.

Here the key word to know is pascal, (P), which is a unit of measure for pressure, defined as

pressure = Force / applied area

1 pascal = 1 newton / square metre or

1 P = 1 N/sq.m.

Here, we have been given:

Force = 150 N

Area = 0.25 m^2.

Thus the pressure

= Force / Area

= 150 N / 0.25 m^2

= 150/0.25 N/m^2

= 600 pascals.

[ note that the abbreviations are written in capitals, while the full words, units of measurement, are written without capitalization, since they are no longer proper names]

8 0

3 years ago

A 4.4 m diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad/s. Its total moment of inertia is 1950 k

krek1111 [17]

Answer:

Angular velocity of merry go round is 0.64 $\frac{rad}{s}$ .

Explanation:

Given :

Radius of merry go round $R = \frac{D}{2} = 2.2$ m

Angular velocity of merry go round $\omega = 0.8 \frac{rad}{s}$

Momentum of inertia $I = 1950$ $Kg m^{2}$

Mass of each people $M = 50$ Kg

From the formula of angular momentum conservation,

$L = I\omega$

So initial angular momentum,

$L_{i} = 1950 \times 0.8 = 1560$

Now we calculate the MOI after people jump on merry go round,

$I_{p} =\frac{1}{2} MR^{2}$

But there are four people so we have to multiply with 4 and add merry go round MOI,

$I _{tot} = 1950 + 2\times 50 \times (2.2) ^{2}$

So total MOI after people jump on is,

$I _{tot} = 2434$ $Kg m^{2}$

From conservation of angular momentum,

$L_{i} = L_{f}$

$1560 = 2434 \times \omega_{f}$

So angular velocity is,

$\omega _{f} = \frac{1560}{2434} = 0.64$ $\frac{rad}{s}$

8 0

3 years ago

Which statements describe a situation in which work is being done? Check all that apply.

Sphinxa [80]

Answer: A, D, E

Explanation:

just did it :))

4 0

3 years ago

Read 2 more answers

A ball is projected horizontally from a table 1.0 m high and hits the ground after falling from a time t=0.45s. If the ball trav

photoshop1234 [79]

The initial velocity is $6.7 m/s$

Explanation:

The motion of the ball is a projectile motion, therefore it consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

$x=v_x t$